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djverab [1.8K]
3 years ago
13

A polypeptide in its native conformation has weak interactions between its R groups. However, when that same polypeptide is dena

tured, these R groups similarly interact with water. Why, then, is the native structure more stable than the denatured one
Chemistry
1 answer:
sasho [114]3 years ago
8 0

Answer:

A protein is more stable in its native form, because apart of weak interactions between R groups, it also presents other stronger interactions, as those including covalent bonds  

Explanation:

For example, covalent bonds between sulfur atoms when disulfide bridges are built.  These links are very difficult to break and maintains the protein shape.  Disulfide bonds are a few but they use to incide in the structure of native proteins

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Answer: Option (b) is the correct answer.

Explanation:

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3 years ago
Calculate the volume in dm3 occupied by 26.4 g of carbon dioxide​
Mama L [17]
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\\ \sf\longmapsto Density=\dfrac{Mass}{Volume}

\\ \sf\longmapsto Volume=\dfrac{Mass}{Density}

\\ \sf\longmapsto Volume=\dfrac{0.0264}{1564}

\\ \sf\longmapsto Volume=1.687m^3=1.69m^3

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\\ \sf\longmapsto Volume=1.69(1000)=1690dm^3

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