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Answer:
13mL
Explanation:
Step 1:
The balanced equation for the reaction. This is given below:
HNO3 + KOH —> KNO3 + H2O
From the balanced equation above, we obtained the following data:
Mole ratio of the acid (nA) = 1
Mole ratio of the base (nB) = 1
Step 2:
Data obtained from the question.
This includes the following:
Molarity of the acid (Ma) = 6M
Volume of the acid (Va) =?
Volume of the base (Vb) = 39mL
Molarity of the base (Mb) = 2M
Step 3:
Determination of the volume of the acid.
Using the equation:
MaVa/MbVb = nA/nB, the volume of the acid can be obtained as follow:
MaVa/MbVb = nA/nB
6 x Va / 2 x 39 = 1/1
Cross multiply to express in linear form
6 x Va = 2 x 39
Divide both side by 6
Va = (2 x 39)/6
Va = 13mL
Therefore, the volume of the acid (HNO3) needed for the reaction is 13mL
The molarity of the solution can be used to give the moles and the volume of the solution. The 0.0140 M sodium thiosulfate needs 225 ml of volume.
<h3>What is molarity?</h3>
Molarity is the property of the solution that is given by the ratio of the moles of the solute to the volume of the solution in liters.
Given,
Molarity of Sodium thiosulfate = 0.0140 M
Mass of solute (AgBr) = 0.590 gm
Molar mass of AgBr = 187.77 g/mol
First moles from the mass can be calculated as,
Moles = mass ÷ molar mass
n = 0.590 g ÷ 187.77 g/mol
= 0.00314 moles
Now, the volume of the solution from molarity is calculated as,
Volume = moles ÷ molarity
= 0.00314 moles ÷ 0.0140
= 0.225 L
Therefore, 225 mL is the volume required.
Learn more about molarity here:
brainly.com/question/13889022
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