Answer:
oof idk I would suggest looking at an example and try going off that
Answer:
<em><u>Unit</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>quantity</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>constant</u></em><em><u> </u></em><em><u>magnitude</u></em><em><u> </u></em><em><u>which</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>used</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>measure</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>magnitudes</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>other</u></em><em><u> </u></em><em><u>quantities</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>same</u></em><em><u> </u></em><em><u>nature</u></em><em><u>.</u></em><em><u> </u></em>
Explanation:
<h2>HOPE IT WILL HELP YOU✌✌✌✌✌</h2>
Answer:
0.719M AgNO₃
Explanation:
Based on the reaction:
MgBr₂ + 2AgNO₃ ⇄ 2AgBr + Mg(NO₃)₂
<em>1 mole of magnesium bromide reacts completely with 2 moles of AgNO₃</em>
<em />
To find molarity of AgNO₃ solution we need to determine moles of AgNO₃ and, as molarity is the ratio of moles over liter (13.9mL = 0.0139L). Now, to determine moles of AgNO₃ we need to use the reaction, thus:
<em>Moles AgNO₃:</em>
<em />
Moles of MgBr₂ are:
50.0mL = 0.050L * (0.100mol / L) = 0.00500 moles of MgBr₂.
As the silver nitrate reacts completely and 2 moles of AgNO₃ reacts per mole of MgBr₂:
0.00500 moles MgBr₂ * (2 moles AgNO₃ / 1 mole MgBr₂) =
0.0100 moles of AgNO₃ are in the solution.
And molarity is:
0.0100 moles AgNO₃ / 0.0139L =
<h3>0.719M AgNO₃</h3>
Its FeSO3 or iron(iii)sulfite = Fe2(SO3)3
