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Marianna [84]
3 years ago
11

I need help on science lol

Chemistry
2 answers:
jeyben [28]3 years ago
8 0

Answer: C

Explanation: i think i looked at my notes from 3 months ago when i did this i think C is the best choice let me know after ypu take the test

lara [203]3 years ago
6 0

Answer:

chicken and macaroni

Explanation:

cus

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How many molecules are there in 0.565 moles of C6H14?
Sauron [17]

Answer:

3.4 × 10^23 molecules

Explanation:

To find the number of molecules present in C6H14, we multiply the number of moles in the compound by Avagadro's number (6.02 × 10^23 atoms).

number of molecules = number of moles (mol) × 6.02 × 10^23?

Number of molecules = 0.565 × 6.02 × 10^23

3.4 × 10^23 molecules

6 0
2 years ago
The gas carbon dioxide is a pure substance. Which of the following is true about carbon dioxide ?
uysha [10]

Answer:

Carbon and oxygen are chemically bonded in it.

Explanation:

The other answer choices do not apply for compounds, but rather for mixtures instead.

I appreciate if you would mark me as brainliest!

5 0
3 years ago
If the acceleration is 600 m/s/s and the mass is 300 kg, what force is acting on the object?
vampirchik [111]

Explanation:

Acceleration (a) = 600 m/s²

Mass (m) = 300 kg

Force (F) = ?

We know

F = m * a

= 300 * 600

=180000 Newton

The force acting on the object is 18000 Newton.

5 0
3 years ago
Read 2 more answers
A solution is prepared by mixing 2.17 g of an unknown non-electrolyte with 225.0 g of chloroform. The freezing point of the resu
Deffense [45]

Answer:

The molar mass of the unknown non-electrolyte is 64.3 g/mol

Explanation:

Step 1: Data given

Mass of an unknown non-electrolyte = 2.17 grams

Mass of chloroform = 225.0 grams

The freezing point of the resulting solution is –64.2 °C

The freezing point of pure chloroform is – 63.5°C

kf = 4.68°C/m

Step 2: Calculate molality

ΔT = i*kf*m

⇒ ΔT = The freezing point depression = T (pure solvent) − T(solution) = -63.5°C + 64.2 °C = 0.7 °C

⇒i = the van't Hoff factor = non-electrolyte = 1

⇒ kf = the freezing point depression constant = 4.68 °C/m

⇒ m = molality = moles unknown non-electrolyte / mass chloroform

0.7 °C = 1 * 4.68 °C/m * m

m = 0.150 molal

Step 3: Calculate moles unknown non-electrolyte

molality = moles unknown non-electrolyte / mass chloroform

Moles unknown non-electrolyte = 0.150 molal * 0.225 kg

Moles unknown non-electrolyte = 0.03375 moles

Step 4: Calculate molecular mass unknown non-electrolyte

Molar mass = mass / moles

Molar mass = 2.17 grams / 0.03375 moles

Molar mass = 64.3 g/mol

The molar mass of the unknown non-electrolyte is 64.3 g/mol

6 0
3 years ago
Please help asappp‍♀️!
solniwko [45]
Can you show me the passage?
6 0
3 years ago
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