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kirza4 [7]
3 years ago
8

The fare for a journey of 40km is Rs25 . How much can be travelled for Rs40

Mathematics
1 answer:
exis [7]3 years ago
8 0

Answer:

just add 15 which is  20 :)))))

Step-by-step explanation:


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Answer:

x= 9

Step-by-step explanation:

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PLEASE HELP ME ITS DUE TOMORROW!! THANKS!
leonid [27]
PART A
Change the fractions into improper fractions
pablo - rosa = 4 4/9 - 3 5/12
pablo - rosa = 40/9 - 41/12

Equalize the denominator of the fractions
I equalize them to 36. If the denominator 9 is multiplied by 4, so is the numerator. If the denominator 12 is multiplied by 3, so is the numerator.
pablo - rosa = 40/9 - 41/12
pablo - rosa = (40 × 4)/(9 × 4) - (41 × 3)/(12 × 3)
pablo - rosa = 160/36 - 123/36
pablo - rosa = 37/36

Change it to mixed fraction
pablo - rosa = 37/36
pablo - rosa = 1 1/36

Pablo has 1 1/36 quarts more than Rosa

PART B
Calculate the iced tea Pablo gave to Rosa
Change into proper fraction/improper fraction
iced tea given = 15% × 4 4/9
iced tea given = 15/100 × 40/9
iced tea given = 600/900
iced tea given = 2/3

Calculate Pablo's iced tea after giving
Pablo's = 40/9 - 2/3
Pablo's = 40/9 - (2 × 3)/(3×3)
Pablo's = 40/9 - 6/9
Pablo's = 34/9
Pablo's = 3 7/9

Calculate Rosa's iced tea
Rosa's = 41/12 + 2/3
Rosa's = 41/12 + (2 × 4)/(3 × 4)
Rosa's = 41/12 + 8/12
Rosa's = 49/12
Rosa's = 4 1/12

Pablo has 3 7/9 quarts and Rosa has 4 1/12 quarts
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3 years ago
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If log 5 = p and log 2=q then log 200 can be written in terms of p and q as?
Andrei [34K]
<h3>Answer:  2p + 3q</h3>

Work Shown:

log(200) = log(2^3*5^2)

log(200) = log(2^3) + log(5^2)

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The log rules I used were

log(A*B) = log(A)+log(B)

log(A^B) = B*log(A)

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3 years ago
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