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Anit [1.1K]
3 years ago
8

Two similar cylinders have volumes 125 and 216. The radius of the smaller cylinder is 3. Find the radius of the larger cylinder.

Mathematics
1 answer:
horrorfan [7]3 years ago
6 0

Answer:

The radius of the larger is 3 3/5 cm or 3.6 cm

Step-by-step explanation:

The ratio of the volumes is  that is related to the scale factor cubed

125/216  = (sf) ^3

Taking the cube root of each side

(125/216)^1/3  = (sf) ^3 ^(1/3)

5/6 = (sf)

That means the ratio of the radii is in the same proportion

5/6 = 3/ r

Using cross products

5r = 6*3

5r/5 = 18/5

r = 18/5 = 3 3/5

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Ten times the sum of negative four and a number. Write as an Algebraic expression then simplify
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Answer:

10x(-4+a)

explanation

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2 years ago
The results of a common standardized test used in psychology research is designed so that the population mean is 145 and the sta
anygoal [31]

The value 155 is zero standard deviations from the mean, because x = μ , and therefore z = 0.

<h3>What is Standard Deviation?</h3>

The standard deviation is a measure of the amount of variation or dispersion of a set of values.

The key concept we need to manage here is the z-scores , and we can obtain a z-score using the next formula:

z = (x - μ)/σ      ..............[1]

Where

z is the z-score.

x is the raw score: an observation from the normally distributed data that we want standardize using [1].

μ is the population mean.

σ is the population standard deviation.

These standardized values have always the same probability in the standard normal distribution, and this is the advantage of using it for calculating probabilities for normally distributed data.

A subject earns a score of 155.

From the question, we know that:

x = 155.

μ = 155

σ = 50

Having into account all the previous information, we can say that the raw score, x = 155, is zero standard deviations units from the mean. The subject earned a score that equals the population mean. Then, using [1]:

z = (x - μ)/σ

z = (155 - 155) / 50

z = 0/50

z = 0

As we say before, the z-score "tells us" the distance from the population mean, and in this case this value equals zero:  

x = μ

Therefore, z = 0

So, the value 155 is zero standard deviations from the [population] mean.

Learn more about Standard Deviation from:

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8 0
2 years ago
Can you solve 5a please greatly appreciated.
timurjin [86]
Part I)
 
The module of vector AB is given by:
 lABl = root ((- 3) ^ 2 + (4) ^ 2)
 lABl = root (9 + 16)
 lABl = root (25)
 lABl = 5

 Part (ii)
 The module of the EF vector is given by:
 lEFl = root ((5) ^ 2 + (e) ^ 2)
 We have to:
 lEFl = 3lABl
 Thus:
 root ((5) ^ 2 + (e) ^ 2) = 3 * (5)
 root ((5) ^ 2 + (e) ^ 2) = 15
 Clearing e have:
 (5) ^ 2 + (e) ^ 2 = 15 ^ 2
 (e) ^ 2 = 15 ^ 2 - 5 ^ 2
 e = root (200)
 e = root (2 * 100)
 e = 10 * root (2)
3 0
3 years ago
Udrey used compensation to mentally solve the subtraction problem 5.35−0.07
Licemer1 [7]
The last step you need to do is 5.25+0.03, because you took away 0.03 more than what the question asked so you need to add the 0.03 back, which gets you the final result of 5.28.
6 0
3 years ago
Solve the equation.
lawyer [7]

Answer:

  • x=12
  • x=9

Step-by-step explanation:

1) Eliminate parentheses:

  0.1x +18.8 = -4 +2x

  22.8 = 1.9x . . . . . . . . . add 4 - 0.1x

  12 = x . . . . . . . . . . . . . divide by 1.9

__

2) Eliminate parentheses:

  -16 +4x = 0.8x +12.8

  3.2x = 28.8 . . . . . . . . add 16 - 0.8x

  x = 9 . . . . . . . . . . . . . .divide by 3.2

_____

<em>Comments on the solutions</em>

The expression we add in each case eliminates the constant on one side of the equation and the variable term on the other side. That leaves an equation of the form ...

  variable term = constant

We choose to eliminate the smaller variable term (the one with the coefficient farthest to the left on the number line). Then the constant we eliminate is the on on the other side of the equation. This choice ensures that the remaining variable term has a positive coefficient, tending to reduce errors.

__

You can work these problems by methods that eliminate fractions. Here, the fractions are decimal values, so are not that difficult to deal with. In any event, it is good to be able to work with numbers in any form: fractions, decimals, integers. It can save some steps.

7 0
2 years ago
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