Answer:
The pH of the solution is 2.56.
Explanation:
Given :
Concentration (c) = 0.40 M
Acid dissociation constant = 
The equilibrium reaction for dissociation of 
(weak acid) is,
initially conc. c 0 0
At eqm. 
Dissociation constant is given as:
By solving the terms, we get value of 
No we have to calculate the concentration of hydronium ion or hydrogen ion.
![[H^+]=c\alpha=0.4\times 0.00686832=0.002747 M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3Dc%5Calpha%3D0.4%5Ctimes%200.00686832%3D0.002747%20M)
Now we have to calculate the pH.
![pH=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D)
Therefore, the pH of the solution is, 2.56.
Answer:
<u>The complete question is:</u>
A researcher is using a small molecule inhibitor to manipulate a signaling pathway. This inhibitor prevents phosphorylation and most likely targets
a: phosphatase.
b: ligand-gated ion channel.
c: G protein-coupled receptor.
d: G-protein.
e: receptor kinase.
<u>The correct answer is:</u>
e: receptor kinase.
Explanation:
Kinase is the enzyme that add phosphate groups by transferring them from molecules having high energy (i.e. ATP) to target compound and the process of adding phosphate groups to the target compound is called phosphorylation.
In light of the above explanation, it is clear that kinase is the type of enzyme that involves in phosphorylation therefore, if an inhibitor prevents phosphorylation, it will automatically targets receptor kinase to inhibit the process of phosphorylation.
Answer:
5010J
Explanation:
The following data were obtained from the question:
Mass (m) = 15g
Heat of fusion (ΔHf) = 334J/g
Heat required (Q) =..?
The heat energy required to melt the ice can be obtained as follow:
Q = m·ΔHf
Q = 15 x 334
Q = 5010J
Therefore, the heat energy required to melt the ice is 5010J.
Answer:
See below
Explanation:
(NH4)2SO4 Molar weight (from periodic table)
(N =14 H4 = 4 ) * 2 = 36
S = 32 O4 = 64 TOTAL = 132 gm/mole
N % = ( 2*14) / 132 = 21.2% molar mass = 28 gm
H % = (2 *4) / 132 = 6% molar mass = 8 gm
S % = 32/132 = 24.2 % molar mass = 32 gm
O % = (64) / 132 = 48.5% molar mass = 64 gm
