Answer:
KNO₃(s) + 35,1 kJ → K⁺(aq) + NO₃⁻(aq)
Explanation:
In the reaction:
KNO₃(s) → K⁺(aq) + NO₃⁻(aq)
The <em><u>heat absorbed</u></em> for the reaction (Because the temperature decreases) is:
Q = C×m×ΔT
Where C is specific heat (4,18J/g°C); m is mass (100g); ΔT is (30,0°C-21,6°C = 8,4°C)
Replacing:
Q = 4,18J/g°C×100g×8,4°C
<em><u>Q = 3511 J</u></em>
Now, moles of KNO₃ are:
10,1g×(1mol / 101g) = <em><u>0,1 moles.</u></em>
Heat of solution in kJ/mol is:
3,511 J / 0,1 mol = <em><u>35,1 kJ</u></em>
As the heat was absorbed for the reaction, right answer is:
<em>KNO₃(s) + 35,1 kJ → K⁺(aq) + NO₃⁻(aq)</em>
That means the reaction needs the heat to occurs.
I hope it helps!
The cofficent is 2 for diphosphorus trioxide
I would say #3 I’m sorry if it’s wrong tho
Answer:
10.09 grams
Explanation:
First you need to know the number of moles you are dealing with.
If you know that each mole has 6.022x10²³ of something (in this case of atoms), you can divide 3x10²³ atoms of neons by 6.022x10²³ to obtain the number of moles.
You have 0.5 moles of Neon, so then by the periodic table, you see that the molar mass of neon is 20.18g/mol, so by each mole you have 20.18 grams of neon. Multiply 20.18 grams by 0.5 moles and you got 10.09 grams of Neon
