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svetoff [14.1K]
2 years ago
15

How can you described the energy of a storm

Chemistry
1 answer:
lakkis [162]2 years ago
4 0

Answer:

When the surface water is warm, the storm sucks up heat energy from the water, just like a straw sucks up a liquid. This creates moisture in the air. If wind conditions are right, the storm becomes a hurricane. This heat energy is the fuel for the storm.

Explanation:

I hope this can help you!

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When the oxide of generic metal m is heated at 25.0 °c, only a negligible amount of m is produced. o2m(s ----> m(s o2(g delta
Len [333]
(1) MO₂(s) + C(s) → M(s) + CO₂ (g),  ΔG₁ = 288.9 kJ/mol
(2) C(s) + O₂(g) → CO₂(g),   ΔG₂ = -394.4 kJ/mol
By adding both equations 1 + 2 we get the coupled reaction:
MO₂(s) + 2 C(s) + O₂(g) → M(s) + 2 CO₂(g)
ΔG⁰ = ΔG₁ + ΔG₂ 
       = 288.9 + (-394.4) = -105.5 kJ/mol = -105500 J/mol
Temperature T = 25 + 273.15 = 298.15 K
Molar gas constant R = 8.314 J/mol.K
K = e^{ \frac{-dG0}{RT} }
   = e^{ \frac{105500}{8.314 x 298.15} } 
    = 3.05 x 10¹⁸
6 0
3 years ago
Determine which of the following pairs of reactants will result in a spontaneous reaction at 25°C. None of the above pairs will
Alla [95]

Answer:

Only Fe^{3+}+Mg gives spontaneous reaction.

Explanation:

A redox reaction will be spontaneous if standard reduction potential (E^{0}) of the reaction is positive. Because it leads to negative standard gibbs free energy change (\Delta G^{0}), which is a thermodynamic condition for spontaneity of a reaction.

E^{0}=E^{0}(reduction)-E^{0}(oxidation)

Where E^{0}(reduction) and E^{0}(oxidation) represents standard reduction potential of reduction half cell and standard reduction potential of oxidation half cell.

(1) Oxidation:         Mg-2e^{-}\rightarrow Mg^{2+} ;  E_{Mg^{2+}\mid Mg}^{0}=-2.38V

Reduction:         Fe^{3+}+3e^{-}\rightarrow Fe ; E_{Fe^{3+}\mid Fe}^{0}=-0.04V

So, E^{0}=E_{Fe^{3+}\mid Fe}^{0}-E_{Mg^{2+}\mid Mg}^{0}=(-0.04+2.38)V=2.34V

Hence this pair will give spontaneous reaction.

(2) Similarly as above, E^{0}=E_{Pb^{2+}\mid Pb}^{0}-E_{Au^{+}\mid Au}^{0}=(-0.13-1.69)V=-1.82 V

Hence this pair will give non-spontaneous reaction.

(3) Similarly as above, E^{0}=E_{Ag^{+}\mid Ag}^{0}-E_{Br_{2}\mid Br^{-}}^{0}=(0.80-1.07)V=-0.27 V

Hence this pair will give non-spontaneous reaction.

(4)  Similarly as above, E^{0}=E_{Li^{+}\mid Li}^{0}-E_{Cr^{3+}\mid Cr}^{0}=(-3.04+0.74)V=-2.30 V

Hence this pair will give non-spontaneous reaction.

6 0
3 years ago
An unknown substance has been shown to have metallic bonds.
gladu [14]
This is the correct answer please mark me as brainliest

6 0
3 years ago
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Is cyclohexanol an alkane, alkene, or an alcohol?
Oxana [17]
Cyclohexanol is an Alcohol..........
8 0
3 years ago
Which of the following describes what happens to the atom that was displaced in the reactant compound during a single replacemen
Marysya12 [62]

Answer: It becomes the uncombined element in the product.

Explanation:

The reaction between Zn and HCl is a single displacement reaction according to equation below

Zn + 2HCl —> ZnCl2 + H2

Zn displaces H2 from acid and in the product, hydrogen became the uncombined element.

3 0
3 years ago
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