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poizon [28]
3 years ago
14

What is an acid in chemistry?

Chemistry
2 answers:
Vikentia [17]3 years ago
5 0
An acid in chemistry is anything with a pH level lower than 7.
UNO [17]3 years ago
5 0

Answer:

A liquid (?) below pH 7

Not sure though

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Single strand RNA is made using the genetic instructions from double strand DNA.
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False I’m pretty sure
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Which events occurred during the space race
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Date Significance Soviet Union Mission

August 21, 1957 First intercontinental ballistic missile (ICBM) R-7 Semyorka

October 4, 1957 First artificial satellite First signals from space Sputnik 1

November 3, 1957 First dog in orbit (Laika) Sputnik 2

January 31, 1958 First US satellite, detection of Van Allen radiation belts

Explanation:

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What type of telescope can you use in a bedroom?
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Is the answer because of the ratio of you fart and the smell in ur nose
8 0
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Which laws can be combined to form the ideal gas law?
Morgarella [4.7K]
Answer: Charles's law, Avogadro's law and Boyle's law.

Justification:

Boyle's law states that at constant temperature  PV = constant

Charles law states that at constant pressure V/T = constant

Avogadro's law states that at constant pressure ant temperature, equal volume of gases contain equal number of moles: V/n = constant

Ideal gas law states PV/nT = constant => PV = nT*constant = PV = nTR
7 0
3 years ago
During a combustion reaction, 9.00 grams of oxygen reacted with 3.00 grams of CH4.
Monica [59]

Answer:

0.74 grams of methane

Explanation:

The balanced equation of the combustion reaction of methane with oxygen is:

  • CH₄ + 2 O₂ → CO₂ + 2 H₂O

it is clear that 1 mol of CH₄ reacts with 2 mol of O₂.

firstly, we need to calculate the number of moles of both

for CH₄:

number of moles = mass / molar mass = (3.00 g) /  (16.00 g/mol) = 0.1875 mol.

for O₂:

number of moles = mass / molar mass = (9.00 g) /  (32.00 g/mol) = 0.2812 mol.

  • it is clear that O₂ is the limiting reactant and methane will leftover.

using cross multiplication

1 mol of  CH₄ needs → 2 mol of O₂

???  mol of  CH₄  needs → 0.2812 mol of O₂

∴ the number of mol of CH₄ needed = (0.2812 * 1) / 2 = 0.1406 mol

so 0.14 mol will react and the remaining CH₄

mol of CH₄ left over = 0.1875 -0.1406 = 0.0469 mol

now we convert moles into grams

mass of CH₄ left over = no. of mol of CH₄ left over *  molar mass

                                    = 0.0469 mol * 16 g/mol = 0.7504 g

So, the right choice is 0.74 grams of methane

3 0
3 years ago
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