Explanation:
Let us assume that total mass of the solution is 100 g. And, as it is given that acetic acid solution is 12% by mass which means that mass of acetic acid is 12 g and 88 g is the water.
Now, calculate the number of moles of acetic acid as its molar mass is 60 g/mol.
No. of moles =
=
= 0.2 mol
Molarity of acetic acid is calculated as follows.
Density =
1 g/ml =
volume = 100 ml
Hence, molarity =
=
= 2 mol/l
As reaction equation for the given reaction is as follows.
So, moles of NaOH = moles of acetic acid
Let us suppose that moles of NaOH are "x".
(as 1 L = 1000 ml)
x = 20 L
Thus, we can conclude that volume of NaOH required is 20 ml.
If there weren't any predators, the population of prey would increase and they would starve due to too many mouths to feed.
Answer: the molecular altatude of the supercalifragilistic gene should expand by 100%,
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Explanation:
Answer:
Any binary molecular compound of hydrogen and a Group 6A element above Selenium will be less acidic, so water and dihydrogen sulfide are less acidic in aqueous solution than hydrogen selenide.
Explanation:
Going down in a group increases the atomic radius and a greater atomic radius implyes greater ionic radius.
When ionization takes place in these compounds they yelds protons (hidrogen ion) and an lewis base (anion). The greater the ionic radius the greater its stability, thus the periodic tendency is increaing the acidity of binary hidrogen compounds when going down a group. On the other hand going up a group decreases acidity, so any molecular compound of hydrogen and a Group 6A element above Selenium will be less acidic, so water and dihydrogen sulfide are less acidic in aqueous solution than hydrogen selenide.
Answer: Dissociation constant of the acid is .
Explanation: Assuming the acid to be monoprotic, the reaction follows:
pH of the solution = 6
and we know that
As HA ionizes into its ions in 1 : 1 ratio, hence
As the reaction proceeds, the concentration of acid decreases as it ionizes into its ions, hence the decreases concentration of acid at equilibrium will be:
Dissociation Constant of acid, is given as:
Putting values of in the above equation, we get
Rounding it of to one significant figure, we get