3x^2+11x-4=10x-1
3x^2+11x-10x-4+1=0
3x^2+x-3=0
Δ=1^1-4*3*(-3)=1+36=37
x1=(-1+V37)/6
x2=( -1-V37)/6
Answer:
Step-by-step explanation:
the formula for the circumference of a circle is 2rπ
the formula for the area of a circle is (r^2)π
the formula for the diameter of a circle is 2r
π=3.14
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1. diameter =2r. since diameter=24, r=12
2. circumference=2rπ. since circumference = 314. 314=2rπ r=49.9746
3. circumference=2rπ area=(r^2)π
since r=7, circumference=14π=43.98229 since r=7, area is 49π=153.9380
4. Since the diameter is 20 the radius is 10. so just insert it into the formulas as before: circumference=20π=62.8318 and area=100π=314.15926
5. the formula for the diameter is 2r=d 2(18)=d, 36=d
6. 2rπ=circumference = 2(5)π=10π=31.415926
Hope that helps :)
Answer:
Exact Form:
x = 31/25
Decimal Form:
x = 1.24
Mixed Number Form:
x = 1 6/25
Step-by-step explanation:
Hope this helps
Answer:
B :it is the ratio of the area of the circle to the area of the square from a cross section.
Step-by-step explanation:
had this question on ed2020 and got it right^
Answer:
See below.
Step-by-step explanation:
Here's an example to illustrate the method:
f(x) = 3x^2 - 6x + 10
First divide the first 2 terms by the coefficient of x^2 , which is 3:
= 3(x^2 - 2x) + 10
Now divide the -2 ( in -2x) by 2 and write the x^2 - 2x in the form
(x - b/2)^2 - b/2)^2 (where b = 2) , which will be equal to x^2 - 2x in a different form.
= 3[ (x - 1)^2 - 1^2 ] + 10 (Note: we have to subtract the 1^2 because (x - 1)^2 = x^2 - 2x + 1^2 and we have to make it equal to x^2 - 2x)
= 3 [(x - 1)^2 -1 ] + 10
= 3(x - 1)^2 - 3 + 10
= <u>3(x - 1)^2 + 7 </u><------- Vertex form.
In general form the vertex form of:
ax^2 + bx + c = a [(x - b/2a)^2 - (b/2a)^2] + c .
This is not easy to commit to memory so I suggest the best way to do these conversions is to remember the general method.
