Answer:
Explanation:
\frac{\lambda }{2} is the minimum interplanar spacing which is required for Bragg's diffraction to occur.
Copper conducts electricity
Answer:
i) O m/s² as velocity is constant
ii) 20m/s
iii)Hint:Calculate the area of the graph,that is;below the line, for the first 15 seconds only
Hope this helps.
I didn't have a dollar bill handy. So I conducted an extensive, exhaustive, in-depth, 2-minute internet search to determine the length of one. (I lived in Boston for 6 years and it had a profound effect on me. All during the 2 minutes of my research, I kept mumbling "dorla bill" to myself.) Anyway, the length of a US dorla bill is 6.14 inches.
We want to find out HOW MANY dorla bills it would take. We don't know that number yet, but we need to use it in our math, so we have to use something to put in its place until we find out the actual number. Most people would use 'x'. I'm going to use ' M '.
Length of 1 bill . . . . . 6.14 inches
Length of ' M ' bills . . . . . (6.14 M) inches
Circumference of the Earth at the equator . . . . . 40,075 km
inches in 1 foot . . . . . 12
feet in 1 meter . . . . . 3.28084
meters in 1 km . . . . . 1,000
This is all the outside information we need. The rest is all arithmetic.
==========================================
length of 1 bill, in inches . . . . . 6.14 inches
length of ' M ' bills, in inches . . . . . (6.14 M inches)
length of ' M ' bills, in feet . . . . .(6.14 M inches) x (1 foot/12 inches)
length of ' M ' bills, in meters . . . . .
(6.14 M inches) x (1 foot/12 inches) x (1 meter/3.28084 foots)
length of ' M ' bills, in km . . . . . (6.14 M inches) x(1 foot/12 inches) x(1 meter/3.28084 foots) x(1 km/1,000 m)
. . . . . . . . . . ^ these numbers are equal \/ . . . . . . . . . .
Circumference of the equator . . . . . 40,075 km
==============================================
Gather all the numbers together, and all the units together:
(6.14M x 1 x 1 x 1)/(12 x 3.28084 x 1,000) x (inch-foot-meter-km/inch-foot-meter) = 40,075 km
Do the arithmetic, and cancel out units that appear on both top and bottom:
(0.000155956 M) x (km) = 40,075 km
Divide each side by 0.000155956 km, and you'll have:
M = (40,075 / 0.000155956)
M = 256.96 million bills
============================================
Quick check, just to see if it makes sense:
Round each dorla bill to 6 inches even:
(256.96 million x 6 inches) x (1 ft/12 inch) x (1 mile/5280 ft) = 24,333 miles
Well, the same internet says the equator's circumference is 24,901 miles. YAY ! ! ! As an engineer, I'd say the two numbers match perfectly. So the answer to the question is confirmed to be
256.96 million bills
(2.57 x 10⁸ bills)
Answer: a. 126.21secs
b. 12.621 meters.
Explanation:
Given data:
Speed of tortoise = 0.1m/s.
Speed of hare = 2m/s.
Solution:
a. Distance traveled = Speed* Time
Speed of tortoise = 0.1 m/s
Speed of hare = 20*0.1 m/s = 2 m/s
2 minutes = 2* 60 s = 120 s
Let the time taken for the race be t seconds.
• Distance moved by tortoise
= (0.1 /s)* (t s)
= 0.1*t meter
•Hare has run for a time of (t - 120)s.
distance moved by hare
= Speed * Time
= (2 m/s)*(t- 120)s
= (2t - 240) meter.
Since hare is 20 cm (0.2 m) behind the tortoise, therefore
(0.1*t - 0.2) meter
= (2t - 240) meter
0.1*t - 0.2 = 2t - 240
Collect like terms
239.8 = 1.9t
Divide both sides by 1.9
t = 126.21secs
The race lasted for 126.21secs
b. Length of race
= Distance moved by tortoise
= 0.1*126.21 meter
= 12.621 meter
The length of the race is 12.621 meters.