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3 years ago

Hunters velocity was 4.5 m/s. At the end of his race, his velocity was the same. Which best describes his Movement?

Physics

1 answer:

hjlf3 years ago

8 0

He has no acceleration because his velocity remains constant

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The wind increases to 14 mph from the north. Now what is your airspeed and what direction are you flying? If your destination is

ladessa [460]

Answer:

I-

Explanation:

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4 years ago

When a second student joins the first, the height difference between the liquid levels in the right and left pistons is 40 cm .

vlada-n [284]

Answer:

m = 56.5 kg

Explanation:

Since the addition of mass on one piston caused a change in pressure head at the other. Diameter of the piston calculated is used as 0.46 m

Δm*g / Area = p * g * Δh ..... Eq1

$m = \frac{p*h*A}{g}$

$m = \frac{850 * 0.4 * pi*0.46^2}{4*9.81}\\\\m= 56.5 kg$

8 0

3 years ago

12028You are using a rope to lift a 14.5 kg crate of fruit. Initially you are lifting the crate at 0.500 m/s. You then increase

11Alexandr11 [23.1K]

Ans: 237.5J

Explanation;

WC= T*d

T* dcostheta. But theta=0

= 190* 1.25

= 237.5J

See attached file for diagram

4 0

3 years ago

How much charge flows from a 6.0 v battery when it is connected across a completely discharged 15.7 μf capacitor?

Lilit [14]

The equation Q=CV (Charge = product of Capacitance and potential difference) tells us that the maximum charge that can be stored on a capacitor is equal to the product of it's capacitance and the potential difference across it. In this case the potential difference across the capacitor will be 6.0V (assuming circuit resistance is negligable) and it has a capacitance of 15.7<span>μf or </span> 15.7x10^-6f, therefore charge equals (15.7x10^-6)x6=9.42x10^-5C (Coulombs).

4 0

3 years ago

Un acróbata de 60 kg realiza un acto de equilibrio sobre un bastón. El extremo del bastón, en contacto con el piso, tiene un áre

vivado [14]

Answer:

Pressure, $P=6.39\times 10^6\ Pa$

Explanation:

A 60 kg acrobat performs a balancing act on a cane. The end of the cane, in contact with the floor, has an area of 0.92 cm2. Calculate the pressure the cane exerts on the floor (neglect the weight of the cane).

We have,

Mass of acrobat, m = 60 kg

The end of the cane, in contact with the floor, has an area of, $A=0.92\ cm^2=0.92\times 10^{-4}\ m^2$

It is required to find the the pressure the cane exerts on the floor. Pressure exerted by an object is defined as the force acting per unit its area. Its formula is written as :

$P=\dfrac{F}{A}\\\\P=\dfrac{mg}{A}\\\\P=\dfrac{60\times 9.8}{0.92\times 10^{-4}}\\\\P=6.39\times 10^6\ Pa$

So, the pressure the cane exerts on the floor is $6.39\times 10^6\ Pa$ .

3 0

3 years ago