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Shkiper50 [21]
3 years ago
8

Hunters velocity was 4.5 m/s. At the end of his race, his velocity was the same. Which best describes his Movement?

Physics
1 answer:
hjlf3 years ago
8 0
He has no acceleration because his velocity remains constant
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The answer is 45 degree angle

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Which two of the senses are considered chemical senses
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The chemical senses are the senses of smell (olfaction) and taste (gustation).
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Joanna learned from customer satisfaction surveys that diners in her restaurant wanted to be able to make substitutions. She has
Dmitry [639]

Answer:

standards

Explanation:

Based on the information provided within the question in regards to the situation at hand it can be said that Joanna is demonstrating a standards gap. this is a gap caused by the difference between the customer service standards a company has created for itself and the expectations the company believes that the customers have for that company. Since Joanna did not tell all the servers of the customers expectations then the ones who do not know will not be able to provide this service to those customers, thus the restaurant will not be able to meet it's customer service standards.

3 0
4 years ago
A pickup truck and a hatchback car start at the same position. If the truck is moving at a constant 33.9m/s and the hatchback ca
4vir4ik [10]

Answer:

s = 589.3 m

Explanation:

Let the truck and car meet at a distance = s  m

The truck is moving at constant velocity = v

so s= v * t ---------- (1)

car:

Vi = 0 m/s

a = 3.9 m/s²

s = Vi* t + 1/2 a t²

s= 0 * t +  1/2 a t²

s =  1/2 a t²   ----------- (2)

compare equation (1)  and equation (2)

s= v * t = 1/2 a t²

⇒ v * t = 1/2 a t²

⇒ t = 2 * v/ a

⇒ t = (2 * 33.9 )/ 3.9

⇒ t = 17. 38 s

Now

from equation (1)

s= v * t

s= 33.9 * 17.38

⇒ s = 589.3 m

3 0
3 years ago
2. Two identical conducting spheres are placed with their centers 0.30 m apart. One is given a charge of 12 x 10-9 C and the oth
Maru [420]

Answer:

A. -2.16 * 10^(-5) N

B. 9 * 10^(-7) N

Explanation:

Parameters given:

Distance between their centres, r = 0.3 m

Charge in first sphere, Q1 = 12 * 10^(-9) C

Charge in second sphere, Q2 = -18 * 10^(-9) C

A. Electrostatic force exerted on one sphere by the other is:

F = (k * Q1 * Q2) / r²

F = (9 * 10^9 * 12 * 10^(-9) * -18 * 10^(-9)) / 0.3²

F = -2.16 * 10^(-5) N

B. When they are brought in contact by a wire and are then in equilibrium, it means they have the same final charge. That means if we add the charges of both spheres and divided by two, we'll have the final charge of each sphere:

Q1 + Q2 = 12 * 10^(-9) + (-18 * 10^(-9))

= - 6 * 10^(-9) C

Dividing by two, we have that each sphere has a charge of -3 * 10^(-9) C

Hence the electrostatic force between them is:

F = [9 * 10^9 * (-3 * 10^(-9)) * (-3 * 10^(-9)] / 0.3²

F = 9 * 10^(-7) N

7 0
3 years ago
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