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Ivahew [28]
3 years ago
7

Answer this and you get 100 points You better answer it quick though

Physics
1 answer:
solong [7]3 years ago
3 0

Answer what? Apologies, but I don't see anything. (。>︿<)

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A particle having a speed of 0.87c has a momentum of 10-16 kg·m/s. what is its mass?
cupoosta [38]
The momentum p of a moving particle is the product between its mass, m, and tis velocity, v:
p=mv
In our problem, we know p=10^{-16}~Kg \cdot m/s and v=0.87c=0.87\cdot 3\cdot10^8~m/s=2.61\cdot 10^8~m/s, and using the relationship mentioned above, we can find the mass m of the particle:
m= \frac{p}{v} =3.8\cdot10^{-25}~Kg
8 0
4 years ago
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ludmilkaskok [199]

Answer:

1) ironing a shirt 2) writing on surfaces 3) working of an eraser

5 0
3 years ago
Starting from rest, a person runs with a constant acceleration, traveling 40 meters in 10 seconds. What is their final velocity?
Assoli18 [71]

Answer:

Final velocity v = 8.944 m/sec

Explanation:

We have given distance S = 40 meters

Time t = 10 sec

As it starts from rest so initial velocity u = 0

From second equation of motion s=ut+\frac{1}{2}at^2

40=0\times 10+\frac{1}{2}a10^2

a=0.8944m/sec^2

Now from first equation of motion v=u+at, here v is final velocity, u is initial velocity, a is acceleration and t is time

So v=u+at=0+0.8944\times 10=8.944m/sec

6 0
4 years ago
A spinning ice skater will speed up if he brings his arms close to his body. Which of the following statements explains this phe
xxMikexx [17]
A. Angular momentum is always conserved would be the correct answer.

This is because like linear momentum (mvmv), angular momentum (r×mvr×mv) is a conserved quantity, where rr is the vector from the center of rotation. For a skater holding a static pose, for each particle making up her body, the contribution in magnitude to the total angular momentum is given by mirivimirivi. Thus bringing in her arms reduces riri for those particles. In order to conserve angular momentum, there is then an increase in the angular velocity.

hope this helps!
7 0
3 years ago
Read 2 more answers
a diver of mass 101 kg jumps upward off a diving board into water. Diving board is 6m above water. Diver has a speed of 1.2m/s.
8090 [49]
When the diver reaches maximum height, the upward velocity will be zero.

We shall use the formula
v^2 = u^2 - 2gh
where 
v = 0 (velocity at maximum height)
u = 1.2 m/s, intial upward velocity
g = -9.8 m/s^2, gravitational acceleration (downward)
h = maximum height attained above the diving board.

Therefore
0 = 1.2^2 - 2*9.8*h
h = 1.2^2/(2*9.8) = 0.0735 m

Answer: 0.074 m (nearest thousandth)
5 0
3 years ago
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