1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Hunter-Best [27]
3 years ago
9

Two swim clubs are having a membership sale. Aqua Plus is offering a two-year membership for $237.36. Water World is offering an

18-month membership for $184.50. Which describes the swim club that has the lower-priced offer?
Mathematics
2 answers:
galina1969 [7]3 years ago
8 0
Divide the price by the number of months to find the monthly rate.
<span>$237.36 ÷ 24 = $9.89 per month </span>
<span>$184.50</span><span> ÷ 18 = $10.25 per month

The two year club, Aqua Plus is cheaper

</span>
DochEvi [55]3 years ago
6 0
Aqua Plus is a better deal.

There is 24 months in two years.

Add $184.50 + $184.50 = $369

If you then subtract $369 - $237.36 = $131.64

Your paying $131.64 for 6 months more than Aqua Plus' deal.

You could buy two memberships at Aqua Plus and have it for four years and it would be cheaper than Water World 1 year and 6 months.
You might be interested in
Math help please will mark brainliest
balu736 [363]

Answer:

you got there answer correct

Step-by-step explanation:

the lines all follow the answer

4 0
3 years ago
Which expression is it equivalent to?
horrorfan [7]
Option A) Is the answer. \boxed{\mathbf{\dfrac{3f^3}{g^2}}}

For this question; You are needed to expose yourselves to popular usages of radical rules. In this we distribute the squares as one-and-a-half fractions as the squares eliminate the square roots. So, as per the use of fraction conversion from roots. It becomes relatively easy to solve and finish the whole process more quicker than everyone else. More easier to remember.

Starting this with the equation editor interpreter for mathematical expressions, LaTeX. Use of different radical rules will be mentioned in between the steps.

Radical equation provided in this query.

\mathbf{\sqrt{\dfrac{900f^6}{100g^4}}}

Divide the numbered values of 900 and 100 by cancelling the zeroes to get "9" as the final product in the next step.

\mathbf{\sqrt{\dfrac{9f^6}{g^4}}}

Imply and demonstrate the rule of radicals. In this context we will use the radical rule for fractions in which a fraction with a denominator of variable "a" representing a number or a variable, and the denominator of variable "b" representing a number or a variable are square rooted by a value of "n" where it can be a number, variable, etc. Here, the radical of "n" is distributed into the denominator as well as the numerator. Presuming the value of variable "a" and "b" to be greater than or equal to the value of zero. So, by mathematical expression it becomes:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{\dfrac{a}{b}} = \dfrac{\sqrt[n]{a}}{\sqrt[n]{b}}, \: \: a \geq 0 \: \: \: b \geq 0}}

\mathbf{\therefore \quad \dfrac{\sqrt{9f^6}}{\sqrt{g^4}}}

Apply the radical exponential rule. Here, the squar rooted value of radical "n" is enclosing another variable of "a" which is raised to a power of another variable of "m", all of them can represent numbers, variables, etc. They are then converted to a fractional power, that is, they are raised to an exponent as a fractional value with variables constituting "m" and "n", for numerator and denominator places, respectively. So:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^m} = a^{\frac{m}{n}}, \: \: a \geq 0}}

\mathbf{Since, \quad \sqrt{g^4} = g^{\frac{4}{2}}}

\mathbf{\therefore \quad \dfrac{\sqrt{9f^6}}{g^2}}

Exhibit the radical rule for two given variables in this current step to separate the variable values into two new squares of variables "a" and "b" with a radical value of "n". Variables "a" and "b" being greater than or equal to zero.

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}, \: \: a \geq 0 \: \: \: b \geq 0}}

So, the square roots are separated into root of 9 and a root of variable of "f" raised to the value of "6".

\mathbf{\therefore \quad \dfrac{\sqrt{9} \sqrt{f^6}}{g^2}}

Just factor out the value of "3" as 3 × 3 and join them to a raised exponent as they are having are similar Base of "3", hence, powered to a value of "2".

\mathbf{\therefore \quad \dfrac{\sqrt{3^2} \sqrt{f^6}}{g^2}}

The radical value of square root is similar to that of the exponent variable term inside the rooted enclosement. That is, similar exponential values. We apply the following radical rule for these cases for a radical value of variable "n" and an exponential value of "n" with a variable that is powered to it.

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^n} = a^{\frac{n}{n}} = a}}

\mathbf{\therefore \quad \dfrac{3 \sqrt{f^6}}{g^2}}

Again, Apply the radical exponential rule. Here, the squar rooted value of radical "n" is enclosing another variable of "a" which is raised to a power of another variable of "m", all of them can represent numbers, variables, etc. They are then converted to a fractional power, that is, they are raised to an exponent as a fractional value with variables constituting "m" and "n", for numerator and denominator places, respectively. So:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^m} = a^{\frac{m}{n}}, \: \: a \geq 0}}

\mathbf{Since, \quad \sqrt{f^6} = f^{\frac{6}{2}} = f^3}

\boxed{\mathbf{\underline{\therefore \quad Required \: \: Answer: \dfrac{3f^3}{g^2}}}}

Hope it helps.
8 0
3 years ago
A 50-gallon tank is filled with a 40% ethanol solution. How much solution should be drained but and replaced with an 80% ethanol
DIA [1.3K]

How do you create your equations when working on a mixture word problem?

Let's try to think about the general form of a word problem involving mixtures.

In general, we have the following scenario:

a merchant sells two kinds of products (coffee, sweets, etc).

we know the unit prices for both kinds of products and for the final mixture

p

1

US dollars per pound for the first kind of product,

p

2

US dollars per pound for the second kind of product

p

m

US dollars per pound for the mixture

we know the total quantity formed by the mixture of the two products (

q

pounds)

we have to find out the quantities of each product needed to form the mixture

(here we have the variables:

x

denoting the quantity of the first kind of product and

y

denoting the quantity of the second kind of product)

Now, we have sufficient information to work out the equations.

First, we know that the sum of the two quantities is

q

pounds, which gives us the first equation:

x

+

y

=

q

Second, we know that the sale price is the product of quantity and unit price, which gives us the second equation:

p

1

x

+

p

2

y

=

p

m

⋅

q

Now, we have a system of two linear equations that can be easily solved by substitution.

3 0
2 years ago
Me pueden resolver esto porfa
Ivanshal [37]

Answer:

need points for school i have to have 50 points by 3 pm ill owe u promise :)

Step-by-step explanation:

3 0
2 years ago
Let g(x) = -5/?. Find g(g(-1))
IRISSAK [1]

Answer:

-1

Step-by-step explanation:

g(-1) = -5/-1 = 5

g(5) = -5/5

g(g(-1)) = -1

7 0
3 years ago
Other questions:
  • Jason jumped of a cliff into the ocean . His height as a function off time could be models as h(t)=16tsquared + 16t + 480 where
    10·1 answer
  • What is the radian measure of an angle containing 60 degrees?
    15·1 answer
  • Twenty-four minus three times an integer,x, is less than x minus four
    12·1 answer
  • Teresa is maintaining a camp fire. She can keep the fire burning for 444 hours with 666 logs. She wants to know how many logs (y
    9·2 answers
  • You've won a new prize! Go to you
    11·1 answer
  • A television costs $350. If a 7% sales tax is added, what is the total cost of the television?
    11·1 answer
  • Which of these inferences about the two debate teams are true? Check all that apply.
    10·2 answers
  • Evaluate y = 2x + 1 when x= -1
    9·2 answers
  • Heidi’s older sister needs to take either Chemistry (C), Geometry (G), or Physics (P) this year. She can take the class during a
    5·2 answers
  • Can someone please help me with this
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!