Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
Answer:
211 text messages
Step-by-step explanation:
20+(m•0.10)=41.10
41.1-20=21.1÷0.1=211
160 is 100% of 160, 480 is 4 times that. So 400%
Answer:
the 90% of confidence intervals for the average salary of a CFA charter holder
(1,63,775 , 1,80,000)
Step-by-step explanation:
<u>Explanation</u>:-
random sample of n = 49 recent charter holders
mean of sample (x⁻) = $172,000
standard deviation of sample( S) = $35,000
Level of significance α= 1.645
<u> 90% confidence interval</u>


on calculation , we get
(1,63,775 , 1,80,000)
The mean value lies between the 90% of confidence intervals
(1,63,775 , 1,80,000)