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alexandr1967 [171]
4 years ago
13

Select the choice from the list below that most accurately completes the statements below. The first phrase will go in the first

blank of the statement and the second phrase will go in the second blank.
A 1: greater than 2: because of Newton's Second Law
B 1: less than 2: because of Newton's Third Law
C 1: equal to 2: because of Newton's Third Law.
D 1: equal to 2: because of Newton's Second Law
E 1: less than 2: because of Newton's Second Law
F 1: greater than 2: because of Newton's Third Law.

You push a box horizontally along level ground but friction is causing the box to slow down. The magnitude of the friction force from the ground on the box is _________the magnitude of your force. You push a box horizontally along level ground at constant velocity. The magnitude of the friction force from the ground on the box is____________the magnitude of your force. You are standing on a hill where the ground is sloped. The magnitude of the normal force from the ground on you is___________the magnitude of the normal force from you on the ground. You are standing on a hill where the ground is sloped. The magnitude of the normal force from the ground on you is _____________the magnitude of your weight. You are facing your (very large and very strong) friend, Commander Worf. Worf gets very angry and pushes you to the ground. Worf remains stationary (a = 0). The magnitude of the force from Worf on you is __________the magnitude of the force from you on Worf. You are standing at a place where the ground is level. The magnitude of your weight is__________the magnitude of the normal force from the ground on you.
Physics
1 answer:
Rudik [331]4 years ago
8 0

Answer:

this question requires us to use our knowledge of newton's 1st 2nd and 3rd laws to fill in the blank spaces. the words in bold are the answers to the question

Explanation:

1. You push a box horizontally along level ground but friction is causing the box to slow down. The magnitude of the friction force from the ground on the box is greater than the magnitude of your force because of newtons second law

2. You push a box horizontally along level ground at constant velocity. The magnitude of the friction force from the ground on the box is equal to the magnitude of your force because of newtons second law

3. You are standing on a hill where the ground is sloped. The magnitude of the normal force from the ground on you is equal to  the magnitude of the normal force from you on the ground because of newtons third law.

4. You are standing on a hill where the ground is sloped. The magnitude of the normal force from the ground on you is less than the magnitude of your weight because of newtons second law

5. You are facing your (very large and very strong) friend, Commander Worf. Worf gets very angry and pushes you to the ground. Worf remains stationary (a = 0). The magnitude of the force from Worf on you is equal to the magnitude of the force from you on Worf because of newtons third law

6. You are standing at a place where the ground is level. The magnitude of your weight is equal to the magnitude of the normal force from the ground on you newtons second law

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A runner starts from rest and in 3 s reaches a speed of 8 m/s. If we assume that the speed changed at a constant rate (constant
Stells [14]

Answer:

The average speed of the runner is 4 m/s.

Explanation:

Hi there!

The average speed (a.s) is calculated by dividing the traveled distance (d) over the time needed to travel that distance (t):

a.s = d / t

So, let´s find the distance traveled in those 3 s. For that, we can use the equation of position of an object moving in a straight line with constant acceleration:

x = x0 + v0 · t + 1/2 · a · t²

Where:

x = position of the object at time t.

x0 = initial position.

v0 = initial velocity.

t = time.

a = acceleration.

If we place the origin of the frame of reference at the point where the runner starts, then, x0 = 0. Since the runner starts from rest, v0 = 0. So, the equation gets reduced to this:

x = 1/2 · a · t²

We have the time (3 s), so let´s find the acceleration. For that, we can use the equation of velocity of an object moving in a straight line with constant acceleration:

v = v0 + a · t

Where "v" is the velocity at a time "t". Since v0 = 0, then:

v = a · t

At t = 3 s, v = 8 m/s

8 m/s = a · 3 s

8/3 m/s² = a

So let´s find the position of the runner at t = 3 s (In this case, the position of the runner will be equal to the traveled distance):

x = 1/2 · a · t²

x = 1/2 · 8/3 m/s² · (3 s)²

x = 12 m

Now, we can calcualte the average speed:

a.s = d/t

a.s = 12 m / 3 s

a.s = 4 m/s

The average speed of the runner is 4 m/s.

4 0
3 years ago
Algunos estudiantes de tu promoción consideran que se debería aumentar el número de horas semanales de Educación Física. Otros c
Pavlova-9 [17]

La respuesta correcta para esta pregunta abierta es la siguiente.

Te compartimos las tres ideas que te pueden ayudar para hacer tu artículo.

Título:

La Educación Física, una prioridad para las escuelas.

Existe una frase milenaria que se le atribuye a los griegos que dice "Mente sana en cuerpo sano."

Y es muy cierta.

Las escuelas deberían considerar seriamente aumentar el número de horas semanales para la impartición de la educación física por las siguientes razones.

1.- La educación física es vital para el desarrollo físico del estudiante. Desde los grados más básicos, las escuelas deberían fortalecer la enseñanza de la educación física por motivos de salud, y dejar este buen hábito en los alumnos para toda la vida.

2.- La educación física, mejora el rendimiento académico ya que ayuda oxigenando los músculos, fortaleciendo el cerebro para que pueda concentrase mejor, despeja a los alumnos de tal forma que puedan regresar a los salones e clase más "despiertos."

3.- La educación física sirve para introducir la importancia de practicar deporte toda la vida, y hacerlo en la etapa escolar a través de equipos deportivos como el Futbol Americano, el beisbol, el basquetbol, el volibol, el soccer, y otros tantos.

Este idea del trabajo en equipo a través del deporte es muy importante para desarrollar habilidades como el liderazgo, el compromiso, la constancia y el superar la adversidad.

El profesor de educación física debe enseñarte la forma correcta de respirar cuando haces ejercicio, la importancia de la relajación del cuerpo para iniciar una actividad. El profesor debe hacer énfasis en la etapa del calentamiento y el estiramiento para preparar al cuerpo antes de realizar el ejercicio. Así como muchas otras enseñanzas.

Por esa razón, las escuelas deberían considerar seriamente la posibilidad de aumentar las horas de educación física por semana.

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3 years ago
A non-_____ rock has interlocking grains with no specific pattern.
Kazeer [188]
A non <span>foliated </span>rock has interlocking grains with no specific pattern.
3 0
4 years ago
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Which position represents spring in the northern hemisphere
andrey2020 [161]

Position D represents spring for the southern hemisphere. This can be determined because position C is winter This can be determined because position C is winter (the tilt is away from the sun ) and spring follows winter.

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You are standing at rest at a bus stop. A bus moving at a constant speed of 5.00 mm/???????? passes you. When the rear of the bu
neonofarm [45]

Answer:

You run 74.1409 mm and you are running at 11.9311 mm/s

Explanation:

If the bus is moving at a constant speed of 5.00mm/s and you start to run when the bus pass you by 12 mm, the equation that describe the position of the bus is:

Xb = 12.0 mm + (5.00 mm/s)*t

Where t is the time in seconds.

If you start to run toward it with a constant acceleration of 0.960 mm/s2, the equation that describe your position is:

X_y=\frac{1}{2} (0.960\frac{mm}{s^{2}})*t^{2}

So, the time t when you catch up the rear of the bus is the time when Xb is equal to Xy. This is:

X_b=X_y\\12+5t=\frac{1}{2} 0.960t^{2} \\0.48t^{2}-5t-12=0

Then, solving the quadratic equation, we obtain that t is equal to 12.4282 s

So, if we replace this value of t in the equation of Xy, we obtain how far you have run before you catch up with the rear of the bus. This is:

X_y=\frac{1}{2} (0.960\frac{mm}{s^{2}})*12.4282^{2}

Xy = 74.1409 mm

Then, the equation of your velocity a time t can be write as:

Vy=0.960\frac{mm}{s^{2} }*t

So, the velocity when you catch up the rear of the bus is:

Vy=0.960\frac{mm}{s^{2} }*12.4282s

Vy = 11.9311 mm/s

3 0
3 years ago
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