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alexandr1967 [171]
4 years ago
13

Select the choice from the list below that most accurately completes the statements below. The first phrase will go in the first

blank of the statement and the second phrase will go in the second blank.
A 1: greater than 2: because of Newton's Second Law
B 1: less than 2: because of Newton's Third Law
C 1: equal to 2: because of Newton's Third Law.
D 1: equal to 2: because of Newton's Second Law
E 1: less than 2: because of Newton's Second Law
F 1: greater than 2: because of Newton's Third Law.

You push a box horizontally along level ground but friction is causing the box to slow down. The magnitude of the friction force from the ground on the box is _________the magnitude of your force. You push a box horizontally along level ground at constant velocity. The magnitude of the friction force from the ground on the box is____________the magnitude of your force. You are standing on a hill where the ground is sloped. The magnitude of the normal force from the ground on you is___________the magnitude of the normal force from you on the ground. You are standing on a hill where the ground is sloped. The magnitude of the normal force from the ground on you is _____________the magnitude of your weight. You are facing your (very large and very strong) friend, Commander Worf. Worf gets very angry and pushes you to the ground. Worf remains stationary (a = 0). The magnitude of the force from Worf on you is __________the magnitude of the force from you on Worf. You are standing at a place where the ground is level. The magnitude of your weight is__________the magnitude of the normal force from the ground on you.
Physics
1 answer:
Rudik [331]4 years ago
8 0

Answer:

this question requires us to use our knowledge of newton's 1st 2nd and 3rd laws to fill in the blank spaces. the words in bold are the answers to the question

Explanation:

1. You push a box horizontally along level ground but friction is causing the box to slow down. The magnitude of the friction force from the ground on the box is greater than the magnitude of your force because of newtons second law

2. You push a box horizontally along level ground at constant velocity. The magnitude of the friction force from the ground on the box is equal to the magnitude of your force because of newtons second law

3. You are standing on a hill where the ground is sloped. The magnitude of the normal force from the ground on you is equal to  the magnitude of the normal force from you on the ground because of newtons third law.

4. You are standing on a hill where the ground is sloped. The magnitude of the normal force from the ground on you is less than the magnitude of your weight because of newtons second law

5. You are facing your (very large and very strong) friend, Commander Worf. Worf gets very angry and pushes you to the ground. Worf remains stationary (a = 0). The magnitude of the force from Worf on you is equal to the magnitude of the force from you on Worf because of newtons third law

6. You are standing at a place where the ground is level. The magnitude of your weight is equal to the magnitude of the normal force from the ground on you newtons second law

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How much work in joules is required to lift a 23 kg box up from the ground to your waist that is 1.0 meters high, carry it 6 met
PSYCHO15rus [73]

Answer:

2682

Explanation:

Work done is given by :

Work = Force x distance

         =  mg x d

So, work done in lifting the box of 23 kg up to my waist of 1 m high is :

W = mg x d

   = 23 x 9.18 x 1

   = 211.14

Now work done carrying the box horizontally 6 meters across the room is

W = mg x d

   = 23 x 9.18 x 6

   = 1266.84

Work done in placing the box on the shelf that is 5.7 m above the ground is

W = mg x d

   = 23 x 9.18 x 5.7

   = 1203.49

So the total work done is = 211.14 + 1266.84 + 1203.49

                                          = 2681.47

                                          = 2682 (rounding off)

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3 years ago
Matter behaving like a wave rather than like a particle is best illustrated by which phenomenon?
Novay_Z [31]
<span>The photoelectric effect is about electrons being ejected from metals when light is shined on metals. The electrons do not behave like waves in the photoelectric effect. Black body radiation is all about the radiation emitted by warm bodies and not about those bodies behaving like waves. The emission spectra of atoms is all about what light is given off by atoms when electrons in those atoms jump down to lower energy levels from higher levels. That also has nothing to do with matter behaving as a wave. Interference is classically defined as the generation of a new wave with an amplitude modulated according to the waves that interfere to form that new wave. Note its emphasis on the wave part.</span>
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3 years ago
Where is the resistor located on the diagram?
Andrej [43]
The answer is B hope this helps
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4 years ago
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Group elements number 11 to 20 as either metallic, non metallic or metalloid.​
bija089 [108]

Answer:

The elements are grouped into the different substances by color. As you can see, Lithium, Beryllium, Sodium, Magnesium, Aluminum, Potassium, and Calcium are metals out of the first 20 elements.

Hydrogen, Helium, Carbon, Nitrogen, Oxygen, Fluorine, Neon, Phosphorus, Sulfur, Chlorine, and Argon, are non-metals within the first 20 elements.

Boron and Silicon count as Metalloids in the Periodic Table (properties of both metals and non-metals)

reference- socatric q and a

Explanation:

7 0
3 years ago
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A long ramp made of cast iron is sloped at a constant angle θ = 52.0∘ above the horizontal. Small blocks, each with mass 0.42 kg
dezoksy [38]

Answer:

For cast iron we have

h = 0.92 m

For copper

h = 1.05 m

For Lead

h = 1.23 m

For Zinc

h = 2.43 m

Explanation:

As we know that final speed of the block is calculated by work energy theorem

W_f + W_g = \frac{1}{2}mv^2

now we have

-\mu_k mg cos\theta(\frac{h}{sin\theta}) + mgh = \frac{1}{2}mv^2

now we have

v^2 = 2gh - 2\mu_k g h cot\theta

v = \sqrt{2gh(1 - \mu_k cot\theta)}

For cast iron we have

4 = \sqrt{2(9.81)(h)(1 - 0.15cot52)}

h = 0.92 m

For copper

4 = \sqrt{2(9.81)(h)(1 - 0.29cot52)}

h = 1.05 m

For Lead

4 = \sqrt{2(9.81)(h)(1 - 0.43cot52)}

h = 1.23 m

For Zinc

4 = \sqrt{2(9.81)(h)(1 - 0.85cot52)}

h = 2.43 m

4 0
3 years ago
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