You would do
51-5= 46
then you would divide
46/2= 23
so Susan is
23+5=28
Susan is 28 years old and her sister is 23
28+23=51
Distribute -3 to parenthasees
-3(r+9)=-3r-27
now we have
-3r-27=-32
add 27 to both sides
-3r+27-27=27-32
-3r+0=-5
-3r=-5
divide both sides by -3
r=-5/-3
r=5/3
If n = $3 then plug it in
$10 + ($6-$3)
$6-$3 = $3
$10 + $3 = $13
Answer:
Gila Monster is 1.54 times that of Chuckwalla.
Step-by-step explanation:
Given:
Average Length of Gila Monster = 0.608 m
Average Length of Chuckwalla = 0.395 m
We need to find the number of times the Gila monster is as the Chuckwalla.
Solution:
Now we know that;
To find the number of times the Gila monster is as the Chuckwalla we will divide the Average Length of Gila Monster by Average Length of Chuckwalla.
framing in equation form we get;
number of times the Gila monster is as the Chuckwalla = 
Rounding to nearest hundredth's we get;
number of times the Gila monster is as the Chuckwalla = 1.54
Hence Gila Monster is 1.54 times that of Chuckwalla.
You can work this out by rearranging the equation and isolating the x.
4x + 12 = 36
4x = 36 - 12 (I moved the +12 to the other side, which means it becomes -12)
4x = 24 (36 - 12 = 24)
x = 24 / 4 (You need to isolate the x, and because it was being multiplied by 4, I divided both sides by 4 to leave me with just x)
x = 6 (24 divided by 4 is 6).