Answer:
= 4.38 × 10³⁴kgm²/s
Explanation:
Given that,
mass of moon m = 9.5 × 10²²kg
Orbital radius r = 4.28 × 10⁵km
Orbital period T = 28.9days
T = 28.9 × 24 × 60 × 60
= 2,496,960s
Angular momentum of the moon about the planet
L = mvr
L = mr²w
Answer:
(4) A = 3 A, A₂ = 11 A
(5) 7 A
Explanation:
(4)
From the diagram,
A = 3+6+2
A = 11 A
V = A₂R
A₂ = V/R₂............ Equation 1
Given: V = 12 V, R₂ = 4 Ω
Substitute these values into equation 1
A₂ = 12/4
A₂ = 3 A
(5) Applying,
V = IR'
I = V/R'............ Equation 1
Where V = Voltage, I = cuurent, R' = total resistance.
But,
1/R' = (1/3)+(1/4)
1/R' = (3+4)/12
1/R' = 7/12
R' = 12/7 Ω
Given: V = 12 V
Substitute these values into equation 1
I = 12/(12/7)
I = 7 A
Therefore
A = 7 A
We will see it again in <span>28 July 2061.</span>
Explanation:
Whole system will accelerate under the action of applied force. The box will experience the force against the friction and when this force exceeds then the box will move. so
Ff = μs×m1×g
m1×a = μs×m1×g
a = μs×g
The applied force is given by
F = (m1 + m2)×a so
F = μs×g×(m1+m2)
Answer:
He should use 90 for Q3 ⇒ answer A
Explanation:
Lets explain the meaning of Q3
Q1 is the "middle" value in the first half of the data set
Q2 is the median value in the set
Q3 is the "middle" value in the second half of the data set
The data are
76 , 79 , 81 , 83 , 85 , 86 , 89 , 91 , 93
The set has nine numbers, then Q2 is the fifth one
Q2 = 85
The first half of the data are:
76 , 79 , 81 , 83
The second half of the data are:
86 , 89 , 91 , 93
They are four numbers, then the middle one is the average of the
second and the third numbers
Q3 =
<em>He should use 90 for Q3 </em>