Two teams of five trying to shoot in the hoop, the ball is moving around the court by players drippling or passing, the team with the basketball is called offense
Answer: 0.078
Explanation:
Given variables:
R1 = 25.0 , R2 = 64.0 , I1 = 0.200
Step 1: find V
0.200 = v/25
0.200 * 25 = v
5 = v
Step 2: Solve for I2
I = V/R
I = 5/64
I = 0.078125
Hope this helps!
<span>40.7 miles.
For this problem, we want to know the length of the chord created by the line and the circle. So let's first create the equations needed.
The slope intercept equation for a line is:
y = ax + b
the value for a will be the the difference in y divided by the difference in x. We're going from y=61 to y=0 for a chance of -61 and from x=0 to x=62 for a change of 62. So the value of a is
-61/62, giving us the formula
y = -(61/62)x + b
Substituting x = 0, we can calculate b
61 = -(61/62)0 + b
61 = b
So the equation for the line is:
y = -(61/62)x + 61
Now for the equation for the circle. Since the circle is centered at the origin, the equation is:
x^2 + y^2 = 48^2
Now we to calculate the intersections.
y = -(61/62)x + 61
x^2 + y^2 = 48^2
x^2 + (-(61/62)x + 61)^2 = 48^2
x^2 + (3721/3844)x^2 - (3721/31)x + 3721 = 2304
(7565/3844)x^2 - (3721/31)x + 3721 = 2304
(7565/3844)x^2 - (3721/31)x + 1417 = 0
1.968002081x^2 - 120.0322581x + 1417 = 0
And we have a rather ugly quadratic equation which we can solve using the quadratic formula, giving the solutions x = 16.00512574 and x = 44.98681081
Now we need to calculate the y values for those 2 x values.
y = -(61/62)x + 61
y = -(61/62)16.00512574 + 61
y = 45.25302145
y = -(61/62)x + 61
y = -(61/62)44.98681081 + 61
y = 16.73878292
So the 2 endpoints are
(16.00512574, 45.25302145) and (44.98681081, 16.73878292)
The distance between those points can be calculated using the Pythagorean theorem.
sqrt((16.00512574 - 44.98681081)^2 + (45.25302145 - 16.73878292)^2)
= sqrt(-28.98168506^2 + 28.51423853^2)
=
sqrt(839.938069 + 813.0617988)
=
sqrt(1652.999868)
= 40.65710107
And finally, we have the solution of 40.7 miles.</span>
I can't tell right away. The elevator's limit is given in terms of mass, but the four people are listed in terms of their weights. In order to compare them, we'll have to convert one or the other.
The total of the four people's weights is:
John . . . . . . . 850N
Betty . . . . . . . 530N
Robert . . . . . . 740N
Alice . . . . . . . .610N
Total . . . . . . 2,730N
The elevator can't accept more than 300 kg of mass.
The weight of any mass is (mass) x (gravity).
On Earth, 300kg weighs (300kg) x (9.8 m/s²) = 2,940 N.
Wonderful !
2,730N is less than 2,940N.
<em>Yes !</em> According to Otis' engineers, John, Betty, Robert and Alice <em>can safely ride the elevator together</em>, (although Betty and Alice may have a different opinion).