It would surely be helpful if you let us know which angles to measure!
(A) For x representing the cost of one of Tanya's items, her total purchase cost 5x. The cost of one of Tony's items is then (x-1.75) and the total of Tony's purchase is 6(x-1.75). The problem statement tells us these are equal values. Your equation is ...
... 5x = 6(x -1.75)
(B) Subtract 5x, simplify and add the opposite of the constant.
... 5x -5x = 6x -6·1.75 -5x
... 0 = x -10.50
... 10.50 = x
(C) 5x = 5·10.50 = 52.50
... 6(x -1.75) = 6·8.75 = 52.50 . . . . . the two purchases are the same value
(D) The individual cost of Tanya's iterms was $10.50. The individual cost of Tony's items was $8.75.
3x-9=2x+4
3x-9+9=2x+4+9
3x=2x+13
3x-2x=2x-2x+13
x=13
Check:
3(13)-9=2(13)+4
39-9=26+4
30=30
Step-by-step explanation:
![A =(125^{2} + 25^{2} ) (5^{2} - 1)\\A = [(5^{3})^{2} + (5^{2})^{2} ] . (5^{2} - 1)\\A = (5^{6} + 5^{4} ). (5^{2} - 1)\\A = [5^{4} . ( 5^{2} + 5)].(5^{2} - 1) \\A = 5^{4} . (25+ 5). (5^{2} - 1)\\A = 5^{4} . 30. (5^{2} - 1)\\](https://tex.z-dn.net/?f=A%20%3D%28125%5E%7B2%7D%20%2B%2025%5E%7B2%7D%20%29%20%285%5E%7B2%7D%20-%201%29%5C%5CA%20%3D%20%5B%285%5E%7B3%7D%29%5E%7B2%7D%20%20%2B%20%285%5E%7B2%7D%29%5E%7B2%7D%20%5D%20.%20%285%5E%7B2%7D%20-%201%29%5C%5CA%20%3D%20%285%5E%7B6%7D%20%20%2B%205%5E%7B4%7D%20%29.%20%285%5E%7B2%7D%20-%201%29%5C%5CA%20%3D%20%5B5%5E%7B4%7D%20.%20%28%205%5E%7B2%7D%20%20%2B%205%29%5D.%285%5E%7B2%7D%20-%201%29%20%5C%5CA%20%3D%205%5E%7B4%7D%20.%20%2825%2B%205%29.%20%285%5E%7B2%7D%20-%201%29%5C%5CA%20%3D%205%5E%7B4%7D%20.%2030.%20%285%5E%7B2%7D%20-%201%29%5C%5C)
Since 30 is divisible by 3
Thus, A is divisible by 3
Good luck!
Answer:
Step-by-step explanation:
g(-2)=2(-2)^3+3(-2)^2-3(-2)+4=-16+12+6+4=6
g(-1)=2(-1)^3+3(-1)^2-3(-1)+4=-2+3+3+4=8
it does not change sign ,so there is no real zero between -2 and -1.
