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Anvisha [2.4K]
3 years ago
9

A 0.167-g sample of an unknown compound contains 0.00278 mol of the compound. Elemental analysis of the acid gives the following

percentages by mass: 40.00% C; 6.71% H; 53.29% O.
Chemistry
1 answer:
ratelena [41]3 years ago
8 0

Answer:

Emperical formula of the acid is CH2O

Molecular formula is C2H4O2

Explanation:

C. H. O

% by mass. 40. 6.71 53.29

MW. 12. 1. 16

Mole 40/12. 6.71/1. 53.29/16

3.33. 6.71. 3.33

3.33/3.33 6.71/3.33 3.33/3.33

1. 2. 1

Emperical Formula (EF): CH2O

Molecular Formula (MF)

Molecular Weight (MW) of acid = mole/mass = 0.00278/0.167 = 60g/mol

MF = (EF)n = 60

(CH2O)n = 60

(12+2+16)n = 60

30n = 60

n = 60/30 = 2

Molecular formula = (EF)n = (CH2O)2 = C2H4O2

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Q = 0.64² × 0.38

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Question 1<br>Which of the following is a false​
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A pycnometer is a precisely weighted vessel that is used for highly accurate density determinations. Suppose that a pycnometer h
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Mass of water ,m'= m - M = 45.65 g -  27.60 g =18.05 g

Volume of pycnometer = Volume of water present in it = V

Density=\frac{Mass}{Volume}

V=\frac{m'}{d}=\frac{18.05 g}{0.9982 g/cm^3}=18.08 cm^3

2) Mass of metal , water and pycnometer = 56.83 g

Mass of metal,M' =  9.5 g

Mass of water when metal and water are together ,m''= 56.83 g - M'- M

56.83 g - 9.5 g - 27.60 g = 19.7 g

Volume of water when metal and water are together = v

v=\frac{m''}{d}=\frac{19.7 g}{0.9982 g/cm^3}=19.73 cm^3

Density of metal = d'

Volume of metal = v' =\frac{M'}{d'}

Difference in volume will give volume of metal ingot.

v' = v - V

v'=19.73 cm^3-18.08 cm^3=

v'=1.65 cm^3

Since volume cannot be in negative .

Density of the metal =d'

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d- Scientists have to follow government rules made to protect people.

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The molarity of the resulting solution obtained by diluting the stock solution is 3 M

<h3>Data obtained from the question </h3>
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  • Volume of stock solution (V₁) = 500 mL
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<h3>How to determine the molarity of diluted solution </h3>

M₁V₁ = M₂V₂

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