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adell [148]
2 years ago
10

What volume of 10,0 M H2SO4 is required to prepare 4.0 L of 0.50 M H2SO4?

Chemistry
1 answer:
Evgesh-ka [11]2 years ago
8 0

Answer: A)  0.20 L

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

According to the neutralization law,

M_1V_1=M_2V_2

where,

M_1 = molarity of stock H_2SO_4 solution = 10.0 M

V_1 = volume of stock H_2SO_4   solution = ?

M_2 = molarity of dilute H_2SO_4  solution = 0.50 M

V_2 = volume of dilute H_2SO_4  solution = 4.0 L

10.0\times V_1=0.50\times 4.0

V_1=0.20L

Therefore, the volume of 10.0 M H_2SO_4 solution needed to prepare 4.0 L of 0.50 M H_2SO_4 is 0.20 L

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Explanation:

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The ideal gas constant, R has several different values that could be used. Which quantity causes these differences? pressure tem
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<span>What reaction??? </span>

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