Question

What volume of 10,0 M H2SO4 is required to prepare 4.0 L of 0.50 M H2SO4?

Answer 1

Answer: A)  0.20 L

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

According to the neutralization law,

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of stock $H_2SO_4$ solution = 10.0 M

$V_1$ = volume of stock $H_2SO_4$   solution = ?

$M_2$ = molarity of dilute $H_2SO_4$  solution = 0.50 M

$V_2$ = volume of dilute $H_2SO_4$  solution = 4.0 L

$10.0\times V_1=0.50\times 4.0$

$V_1=0.20L$

Therefore, the volume of 10.0 M $H_2SO_4$ solution needed to prepare 4.0 L of 0.50 M $H_2SO_4$ is 0.20 L