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Zolol [24]
4 years ago
7

To change from one unit to another in the metric system multiply or divide by multiples of what number?

Physics
1 answer:
Katarina [22]4 years ago
5 0

Answer:

10

Explanation:

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Define energy and provide examples of potential and kinetic energy
In-s [12.5K]

Energy is the capacity for doing work..

Kinetic energy - Moving car

Potential energy - flowing water up the hill

6 0
3 years ago
The following time dependent force is applied to a 2 kg block that is initially at rest on a frictionless and horizontal surface
DerKrebs [107]

Answer:

The displacement of the block is 9 m.

Explanation:

Given that,

Mass of block = 2 kg

Time = 3 sec

The force is

F(t)=4t

The acceleration is

a=\dfrac{F}{m}

Put the value into the formula

a=\dfrac{4t}{2}

a=2t

We need to calculate the velocity

Using formula of acceleration

v=\int_{0}^{t}{a dt}

Put the value into the formula

v=\int_{0}^{3}(2t dt)

v=(\dfrac{2t^2}{2})_{0}^{3}

v=(t^2)_{0}^{3}

v=9\ m/s

We need to calculate the displacement

Using formula of velocity

s=\int_{0}^{3}(v dt)

s=(t^2)_{0}^{3}

s=(\dfrac{t^3}{3})_{0}^{3}

s=9\ m/s

Hence, The displacement of the block is 9 m.

8 0
3 years ago
Read 2 more answers
How does simple machines make work easier?
drek231 [11]
They make it so you would exert less force and make things easier to move
5 0
3 years ago
Read 2 more answers
1. Most of the stars on the HR Diagram are classified as which type of star?
xenn [34]

Answer:

1. Main Sequence - middle life 17

2. red

3. blue

4. White dwarf stars are much hotter than Red Supergiants 15. List the color of the stars from hottest to coldest: Blue, White, Yellow, Orange, Red 16.

5. red giants

Explanation:

Main sequence stars have a Morgan-Keenan luminosity class labeled V. red giant and supergiant stars (luminosity classes I through III) occupy the region above the main sequence. They have low surface temperatures and high luminosities which, according to the Stefan-Boltzmann law, means they also have large radii. White dwarf stars are much hotter than Red Supergiants 15. List the color of the stars from hottest to coldest: Blue, White, Yellow, Orange, Red 16. The hottest stars are the blue stars. A star appears blue once its surface temperature gets above 10,000 Kelvin, or so, a star will appear blue to our eyes. The lowest temperature stars are red while the hottest stars are blue. Astronomers are able to measure the temperatures of the surfaces of stars by comparing their spectra to the spectrum of a black body. Most stars, including the sun, are "main sequence stars," fueled by nuclear fusion converting hydrogen into helium. ...

As stars begin to die, they become giants and supergiants (above the main sequence).

5 0
3 years ago
Read 2 more answers
A square is 1.0 m on a side. Point charges of +4.0 μC are placed in two diagonally opposite corners. In the other two corners ar
finlep [7]

Answer:

<em>B) 1.0 × 10^5 V</em>

Explanation:

<u>Electric Potential Due To Point Charges </u>

The electric potential produced from a point charge Q at a distance r from the charge is

\displaystyle V=k\frac{Q}{r}

The total electric potential for a system of point charges is equal to the sum of their individual potentials. This is a scalar sum, so direction is not relevant.

We must compute the total electric potential in the center of the square. We need to know the distance from all the corners to the center. The diagonal of the square is

d=\sqrt2 a

where a is the length of the side.

The distance from any corner to the center is half the diagonal, thus

\displaystyle r=\frac{d}{2}=\frac{a}{\sqrt{2}}

\displaystyle r=\frac{1}{\sqrt{2}}=0.707\ m

The total potential is  

V_t=V_1+V_2+V_3+V_4

Where V1 and V2 are produced by the +4\mu C charges and V3 and V4 are produced by the two opposite charges of \pm 3\mu\ C. Since all the distances are equal, and the charges producing V3 and V4 are opposite, V3 and V4 cancel each other. We only need to compute V1 or V2, since they are equal, but they won't cancel.

\displaystyle V_1=V_2=k\frac{Q}{r}=9\times 10^9 \frac{4\times 10^{-6}}{0.707}

V_1=V_2=50912\ V

The total potential is

V_t=50912\ V+50912\ V=1\times 10^5\ V

\boxed{V_t=1\times 10^5\ V}

6 0
4 years ago
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