In SI units, what is the magnitude the net force acting on a 1,152 kg car that accelerates uniformly along a straight line from
1 answer:
Answer:
Fnet = 14515.2 Newton
Explanation:
Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.
Mathematically, net force is given by the formula;
Where;
- Fnet is the net force.
- Fapp is the applied force.
- Fg is the force due to gravitation.
Given the following data;
Mass = 1,152 kg
Initial velocity, u = 3m/s
Final velocity, v = 17m/s
Time, t = 5 seconds
To find the magnitude of the net force;
First of all, we would determine the acceleration of the car.
Acceleration = (v-u)/t
Acceleration = (17 - 3)/5
Acceleration = 14/5
Acceleration = 2.8m/s
To find the applied force;
Fapp = mass * acceleration
Fapp = 1,152 * 2.8
Fapp = 3225.6 N
Next, we would find the force exerted on the car due to gravity.
Fg = mass * acceleration due to gravity
We know that acceleration due to gravity is equal to 9.8m/s²
Fg = 1152 * 9.8
Fg = 11289.6N
Substituting the values into the equation, we have;
Fnet = 3225.6 + 11289.6
Fnet = 14515.2 Newton
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a)
b) See plot attached
c) 10.0 m
d) 0.500 cm
Explanation:
a)
The position of the tip of the lever at time t is described by the equation:
(1)
The generic equation that describes a wave is
(2)
where
A is the amplitude of the wave
T is the period of the wave
t is the time
By comparing (1) and (2), we see that for the wave in this problem we have
Therefore, the period is
b)
The sketch of the profile of the wave until t = 4T is shown in attachment.
A wave is described by a sinusoidal function: in this problem, the wave is described by a sine, therefore at t = 0 the displacement is zero, y = 0.
The wave than periodically repeats itself every period. In this sketch, we draw the wave over 4 periods, so until t = 4T.
The maximum displacement of the wave is given by the value of y when , and from eq(1), we see that this is equal to
y = 0.500 cm
So, this is the maximum displacement represented in the sketch.
c)
When standing waves are produced in a string, the ends of the string act as they are nodes (points with zero displacement): therefore, the wavelength of a wave in a string is equal to twice the length of the string itself:
where
is the wavelength of the wave
L is the length of the string
In this problem,
L = 5.00 m is the length of the string
Therefore, the wavelength is
d)
The amplitude of a wave is the magnitude of the maximum displacement of the wave, measured relative to the equilibrium position.
In this problem, we can easily infer the amplitude of this wave by looking at eq.(1).
And by comparing it with the general equation of a wave:
In fact, the maximum displacement occurs when the sine part is equal to 1, so when
which means that
And therefore in this case,
So, this is the displacement.
