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svlad2 [7]
3 years ago
14

In SI units, what is the magnitude the net force acting on a 1,152 kg car that accelerates uniformly along a straight line from

a speed of 3 m/s to a speed of 17 m/s in 5s?
Physics
1 answer:
geniusboy [140]3 years ago
7 0

Answer:

Fnet = 14515.2 Newton

Explanation:

Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.

Mathematically, net force is given by the formula;

Fnet = Fapp + Fg

Where;

  • Fnet is the net force.
  • Fapp is the applied force.
  • Fg is the force due to gravitation.

Given the following data;

Mass = 1,152 kg

Initial velocity, u = 3m/s

Final velocity, v = 17m/s

Time, t = 5 seconds

To find the magnitude of the net force;

First of all, we would determine the acceleration of the car.

Acceleration = (v-u)/t

Acceleration = (17 - 3)/5

Acceleration = 14/5

Acceleration = 2.8m/s

To find the applied force;

Fapp = mass * acceleration

Fapp = 1,152 * 2.8

Fapp = 3225.6 N

Next, we would find the force exerted on the car due to gravity.

Fg = mass * acceleration due to gravity

We know that acceleration due to gravity is equal to 9.8m/s²

Fg = 1152 * 9.8

Fg = 11289.6N

Substituting the values into the equation, we have;

Fnet = 3225.6 + 11289.6

Fnet = 14515.2 Newton

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A golf club rotates 215 degrees and has a length (radius) equal to 29 inches. The time it took to swing the club was 0.8 seconds
vichka [17]

Answer:

The average linear velocity (inches/second) of the golf club is 136.01 inches/second

Explanation:

Given;

length of the club, L = 29 inches

rotation angle, θ = 215⁰

time of motion, t = 0.8 s

The angular speed of the club is calculated as follows;

\omega = (\frac{\theta}{360} \times 2\pi, \ rad) \times \frac{1}{t} \\\\\omega =  (\frac{215}{360} \times 2\pi, \ rad) \times \frac{1}{0.8 \ s} \\\\\omega = 4.69 \ rad/s

The average linear velocity (inches/second) of the golf club is calculated as;

v = ωr

v = 4.69 rad/s  x  29 inches

v = 136.01 inches/second

Therefore, the average linear velocity (inches/second) of the golf club is 136.01 inches/second

8 0
3 years ago
Little Red travels 30 miles to her grandmother's house at a steady speed of 10 miles per hour. If she leaves at 2pm, what time w
3241004551 [841]

Little Red will arrive at her grandmother's house at 5 PM :)

30/10 = 3

2 + 3 = 5

8 0
3 years ago
What if the earth were larger?
Slav-nsk [51]

The answer is C. Gravity would pull too hard on the atmosphere.

8 0
3 years ago
4. How far apart are a proton and electron if they exert an attractive force of 3 N on one another?
alexandr402 [8]

Answer:

8.76\cdot 10^{-15}m

Explanation:

The magnitude of the electrostatic force between two charges is given by the equation:

F=k\frac{q_1 q_2}{r^2}

where:

k=9\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the two charges

r is the separation between the two charges

And the force is:

- Attractive if the charges have opposite sign

- Repulsive if the charges have same sign

In this problem, we have:

F = 3 N is the force between the proton and the electron

q_1=q_2=1.6\cdot 10^{-19}C is the magnitude of the charge of the proton and the electron

Therefore, solving for r, we find the separation between the two particles:

r=\sqrt{\frac{kq_1 q_2}{F}}=\sqrt{\frac{(9\cdot 10^9)(1.6\cdot 10^{-19})^2}{3}}=8.76\cdot 10^{-15}m

5 0
3 years ago
What is the unit of measurement used to describe the size of a protein in gel electrophoresis?.
Mashutka [201]

Daltons, a unit of molecular weight, are used to measure protein size. The mass of a hydrogen atom, which is 1.66 x 10-24 grammes, is considered to be one Dalton. Since the majority of proteins have masses in the thousands of Dalton range, the term kilodalton (kDa) is frequently used to refer to the molecular weight of proteins.

  • Daltons (Da) or kilodaltons, which are units of molecular weight, are typically used to measure proteins (kDa). By comparing the sizes of standard molecular weight markers of known size that were run in parallel with the unknown samples during gel electrophoresis, one can estimate the sizes of DNA, RNA, or protein molecules that were separated on gels.
  • Different techniques have been used to assess the electrophoretic mobilities of DNA polymer fragments in an agarose gel and then convert those measurements to lengths using the reciprocal method. The length estimations can be greatly distorted by the measurement technique.

To know more about protein size

brainly.com/question/13052303

#SPJ4

4 0
1 year ago
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