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Kobotan [32]
3 years ago
11

A ford F-250 pulls a 1000-kg car with a net force of 2000 N. What is the acceleration of the car A=F/m

Physics
1 answer:
vfiekz [6]3 years ago
5 0

Answer:

2ms^2

Explanation:

A = 2000 divided by 1000

A= 2

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How far will an object move in 6 s if its average
Dafna11 [192]

Given:-

  • Time taken by the particle (t) = 6 s
  • Average speed (v) = 40 m/s

To Find: Distance (s) travelled by the particle.

We know,

s = vt

where,

  • s = Distance travelled,
  • v = Speed &
  • t = Time taken.

Putting the values,

s = (40 m/s)(6 s)

→ s = 240 m ...(Ans.)

6 0
3 years ago
When are the displacement and acceleration equal to zero for the motion of a mass on a spring?
aliina [53]

Answer:

Option B is the right answer.

5 0
4 years ago
A rock is thrown at a window that is located 16.0 m above the ground. The rock is thrown from the ground at an angle of 40.0° ab
Angelina_Jolie [31]

Answer:

x = 27.3 m

Explanation:

This is a projectile launching exercise, let's start by looking for the time it takes for the rock to reach the height of the window.

Let's use trigonometry to find the velocities of the rock

           sin 40 = v_{oy} / v

           cos 40 = v₀ₓ / v

           v_{oy}= v sin 40

           v₀ₓ = v cos 40

           v_{oy} = 30 sin 40 = 19.28 m / s

           v₀ₓ = v cos 40

           v₀ₓ = 30 cos 40 = 22.98 m / s

we look for the time

        v_{y}^2 = v_{oy}^2 - 2 g y

         v_{y}^2 = 19.28 2 - 2 9.8 16 = 371.71 - 313.6 = 58.118

        v_{y} = 7.623 m / s

we calculate the time

          v_{y} = v_{oy} - gt

          t = (v_{oy} - v_{y}) / g

          t = (19.28 -7.623) / 9.8

          t = 1,189 s

           

since the time is the same for both movements let's use this time to find the horizontal distance

           x = v₀ₓ t

           x = 22.98 1,189

           x = 27.3 m

4 0
4 years ago
Can the number of protons in an element ever change?
adelina 88 [10]
The number of protons in any element can never change.
4 0
3 years ago
Read 2 more answers
The greatest ocean depths on the earth are found in the marianas trench near the philippines. calculate the pressure due to the
tensa zangetsu [6.8K]
First, let us derive our working equation. We all know that pressure is the force exerted on an area of space. In equation, that would be: P = F/A. From Newton's Law of Second Motion, force is equal to the product of mass and gravity: F = mg. So, we can substitute F to the first equation so that it becomes, P = mg/A. Now, pressure can also be determined as the force exerted by a fluid on an area. This fluid can be measure in terms of volume. Relating volume and mass, we use the parameter of density: ρ = m/V. Simplifying further in terms of height, Volume is the product of the cross-sectional area and the height. So, V = A*h. The working equation will then be derived to be:

P = ρgh

This type of pressure is called the hydrostatic pressure, the pressure exerted by the fluid over a known height. Next, we find the literature data of the density of seawater. From studies, seawater has a density ranging from 1,020 to 1,030 kg/m³. Let's just use 1,020 kg/m³. Substituting the values and making sure that the units are consistent:

P = (1,020 kg/m³)(9.81 m/s²)(11 km)*(1,000 m/1km)
P = 110,068,200 Pa or 110.07 MPa
6 0
3 years ago
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