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Kobotan [32]
3 years ago
11

A ford F-250 pulls a 1000-kg car with a net force of 2000 N. What is the acceleration of the car A=F/m

Physics
1 answer:
vfiekz [6]3 years ago
5 0

Answer:

2ms^2

Explanation:

A = 2000 divided by 1000

A= 2

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 The answer is:  " \frac{9.8 m}{s^2}" .
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the specific heat of water is 4.2 j/c. if it takes 31,500 joules to heat to warm 750 g of water, what was the temperature change
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Q=mC_s \Delta T
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In our problem, the mass of the water is m=750 g, the specific heat is C_s = 4.2 J/g ^{\circ}C and the amount of heat supplied is Q=31500 J, so if we re-arrange the previous formula we find the increase in temperature of the water:
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How much energy from the sun actually reaches the corn answer?
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A small block with mass 0.0400 kg is moving in the xy-plane. The net force on the block is described by the potentialenergy func
OlgaM077 [116]

Answer:

A= 148.92  m/s²

Explanation:

Given that

U(x,y) = (6.00  )x²  - (3.75  )y ³

m= 0.04 kg

Now force in the x-direction

Fx= - dU/dx

U(x,y) = (6.00  )x²  - (3.75  )y ³

dU/dx= 12 x

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dU/dx= 12 x 0.4 = 4.8

So we can say that

Fx= - 4.8 N

From Newtons law

F= m a

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a = -120 m/s²

Acceleration in x direction ,a = -120 m/s²

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F= - dU/dy

U(x,y) = (6.00  )x²  - (3.75  )y ³

dU/dy = 0 - 3.75 x 3 y²

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dU/dy = - 3.75 x 3 x 0.56 x 0.56

dU/dy = - 3.52

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The resultant acceleration

A=\sqrt{a^2+a'^2}

A=\sqrt{120^2+88.2^2}

A= 148.92  m/s²

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3 years ago
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