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hjlf
3 years ago
10

Can anyone help me with this?

Physics
1 answer:
Anika [276]3 years ago
8 0

Answer:

hope it's help you

Explanation:

please mark me brainlest it gives you 25 points bye bye bye bye

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Consider a 2.54-cm-diameter power line for which the potential difference from the ground, 19.6 m below, to the power line is 11
tiny-mole [99]

Answer:

The line charge density is 1.59\times10^{-4}\ C/m

Explanation:

Given that,

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V=EA

V=\dfrac{\lambda}{2\pi\epsilon_{0}r}\times\pi r^2

\lambda=\dfrac{V\times2\epsilon_{0}}{r}

Where, r = radius

V = potential difference

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\lambda=\dfrac{115\times10^{3}\times2\times8.8\times10^{-12}}{1.27\times10^{-2}}

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Explanation:

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