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34kurt
3 years ago
5

Determine the solution for x^2-3x-28 > or equal to 0

Mathematics
1 answer:
omeli [17]3 years ago
8 0
The solutions are:
x = −4,x = 7
Explanation:
X^2−3x−28= 0
We can first factorise this expression by splitting the middle term and then find the solutions:
= x^2−7x+4x−28=0

= x( x−7) + 4( x − 7)=0
=(x+4)(x−7)
Now, we can equate the two factors with zero and find the solutions:
x+4=0,x =−4x−7=0,x=7
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