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kaheart [24]
3 years ago
14

Write the expression in terms of sine and cosine and simplify so that no quotients appear in the final expression. Show work.

Mathematics
1 answer:
AlexFokin [52]3 years ago
7 0
<h3>Answer:</h3>

sec²(x)

<h3>Explanation:</h3>

As required:

... = (sin²(x)/cos²(x))(1 +(cos²(x)/sin²(x))

... = (sin²(x)·(sin²(x)+cos²(x)) / (cos²(x)·sin²(x))

... = 1/cos²(x) = sec²(x)

_____

Alternatively, multiply out the given expression, then use trig identities.

... = tan²(x) + (tan(x)·cot(x))² = tan²(x) +1 = sec²(x)

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There is a sales tax of $6 on an item that costs $64 before tax. The sales tax on a second item is $8.25 . How much does the sec
bulgar [2K]
The second item would be $88 before tax since the tax rate is <span>9.375%</span>
5 0
3 years ago
Solve for x. enter your answer in interval notation using grouping symbols. x^2+15x&lt;-36
Oliga [24]
X²+15x+36<0

at first solve quadratic equation

D=b²-4ac= 225-4*1*36= 81

x=(-b+/-√D)/2a
x=(-15+/-√81)/2= (-15+/-9)/2
x1=(-15-9)/2=-12
x2=(-15+9)/2=-3

we can write x²+15x+36<0 as (x+12)(x+3)<0

(x+12)(x+3)<0 can be 2 cases, because for product to be negative one factor should be negative , and second factor should be positive
 1 case)      x+12<0, and x+3>0,                                            
                       x<-12, and x>-3
(-∞, -12) and(-3,∞) gives empty set

or second case)  x+12>0 and x+3<0
x>-12 and x<-3
(-12,∞) and (-∞,-3)  they are crossing , so (-12, -3)  is a solution of this inequality


3 0
3 years ago
Suppose instead of comparing independent measurements taken from two groups, you used a matched-pairs experiment and one treatme
lina2011 [118]

You should use a T distribution to find the critical T value based on the level of confidence. The confidence level is often given to you directly. If not, then look for the significance level alpha and compute C = 1-alpha to get the confidence level. For instance, alpha = 0.05 means C = 1-0.05 = 0.95 = 95% confidence

Use either a table or a calculator to find the critical T value. When you find the critical value, assign it to the variable t.

Next, you'll compute the differences of each pair of values. Form a new column to keep everything organized. Sum everything in this new column to get the sum of the differences, which then you'll divide that by the sample size n to get the mean of the differences. Call this dbar (combination of d and xbar)

After that, you'll need the standard deviation of the differences. I recommend using a calculator to quickly find this. A spreadsheet program is also handy as well. Let sd be the standard deviation of the differences

The confidence interval is in the form (L, U)

L = lower bound

L = dbar - t*sd/sqrt(n)

U = upper bound

U = dbar + t*sd/sqrt(n)

3 0
3 years ago
I deposited $ 50,000.00 in Chase Bank at 4%. How long my money has to stay in the bank to double ?
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whyu

Step-by-step explanation:

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5 0
3 years ago
Which shows a function for the sequence 16, 8, 4, 2, …?
navik [9.2K]

Answer:

C

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16, 8, 4, 2, …

a = 16

r = 8/16 = ½

f(x) = 16 × (½)^(x - 1)

6 0
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