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zlopas [31]
4 years ago
14

Let the speeds of drivers e and n prior to the collision be denoted by ve and vn, respectively. find v2, the square of the speed

of the two-car system the instant after the collision.
Physics
1 answer:
galina1969 [7]4 years ago
4 0
Thank you for posting your question here at brainly. I hope the answer will help you. Below is the solution:

Make a momentum balance: 
<span>m_e · v_e + m_n · v_n = (m_e + m_n) · v </span>
<span>where v is the speed of the two cars instant after the collision. </span>
<span>Because the cars have the same mass, this simplifies to </span>
<span>v_e + v_n = 2v </span>
<span>The square of the speed instant after collision is: </span>
<span>v² = 1/4·(v_e + v_n)² </span>
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