To find the perpendicular line a y- 2 = 7/3 (x + 5) you must first observe that the slope is m = 7/3, therefore, the slope of the perpendicular line put of the reciprocal, that is, m = - 3/7. So the possible options are A or C, but since the point (-4, 9) must go through the line, we find that the equation that satisfies that is option C.Therefore the perpendicular line that passes through the point (-4, 9) is C. y - 9 = -3/7 (x + 4)
Answer:
It's X
Step-by-step explanation:
C'=1.5
c/c'=d/d'
c/1.5=8
c=12
hope that helps :)
Hello there.
Answer: It is A. 5.4 x 10^-34.
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For option d:
5x - 7y = 10 . . . . . (1)
10x - 14y = 8 . . . . (2)
(1) x 2 => 10x - 14y = 20 . . . . . (3)
(2) - (3) => 0 = -14 [not possible]
Therefore, the set of equations in option d, has no solutions.
