Answer:
<h3>I had an advise that math antics can help u </h3>
Step-by-step explanation:
<h3>Thank you</h3>
Answer:
A) 0.303
The probability that a randomly selected student from the class has brown eyes , given they are male
Step-by-step explanation:
<u>Explanation</u>:-
Given data
Brown Blue Hazel Green
Females 13 4 6 9
Males 10 2 9 12
<em>Let 'B' be the event of brown eyes </em>
<em>Total number of males n(M) = 33</em>
Let B/M be the event of randomly selected student from the class has brown eyes given they are male
<em>The probability that a randomly selected student from the class has brown eyes , given they are male</em>
<em></em>
<em></em>
<em>From table the brown eyes from males = 10</em>
<u>Final answer</u>:-
The probability that a randomly selected student from the class has brown eyes , given they are male
Answer:
X
Step-by-step explanation:
X=input(time) 6 minutes both
Answer:
87.5
Step-by-step explanation:
Area = 11+7
--- x 7
2
OR
Area = a+b/2 x h
Answer: E - S = (-16 and 6)
Step-by-step explanation:1/3 of the 30 decimals in T have an even tenths digit, it follows that 1/3*(30)=10 decimals in T have an even tenths digit.
Hence: Te =list of 10 decimals
Se = sum of all 10 decimals in Te
Ee =estimated sum of all 10 decimals in Te after rounding up.
Remaining 20 decimals in T all have an odd tenths digits.
To =list of this 20 decimals
So = sum of all 20 decimals in To
Eo = estimated sum of 20 decimals in To
Hence,
E = Ee + Eo and S =Se +So, hence:
E-S, =(Ee+Eo) - (Se+So) =(Ee-Se) +(Eo-So)
Ee-Se >10 (0.1)=1
S=10(1.8)+20(1.9) =18+38=56
E=10(2)+20(1)=40
E-S =40-56=-16.
AlsoS=10(1.2)+20(1.1)=34
E=10(2)+20(1)=40
E-S=40-34=6
