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3 years ago

How do I solve 5(4x -5) = 155

1 answer:

5 0

5*(4*x-5)-(155)=0
 5 • (4x - 5) - 155 = 0
 Pull out like factors :
20x - 180 = 20 • (x - 9)
 20 • (x - 9) = 0 Solve : 20 = 0
Solve : x-9 = 0
 Add 9 to both sides of the equation :
 x = 9
hope that helps!!

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Question 6

erastova [34]

It’s 21.9 hope this helps

8 0

3 years ago

What’s the correct answer

vitfil [10]

the answer should be 1/5 because its one out of all the five choices

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3 years ago

The two non-parallel sides of an isosceles trapezoid are each 7 feet long. The longer of the two bases measures 22 feet long. Th

Orlov [11]

The length of the diagonal and the shorter base are 17. 24 feet and 18. 7 feet long respectively.

<h3>How to determine the length</h3>

The cosine rule is given as;

$c = \sqrt{a^2 + b^2 - 2ab cos \alpha }$

c = length of the diagonal

a = base length = 22 feet

b = 7 feet

$c = \sqrt{7^2 + 22^2 - 2 * 7 * 22 cos 40}$

$c = \sqrt{533 - 308 * 0. 7660}$

$c = \sqrt{533 - 235. 93}$

$c = \sqrt{297. 072}$

$c = 17. 24$ feet

Using sine rule

$\frac{a}{sin A } = \frac{c}{sin C}$

$\frac{a}{sin 70} = \frac{17. 24}{sin 40}$

Cross multiply

$a$ × $sin 60$ = $c$ × $sin 70$

$a$ × $0. 8660$ = $17. 24$ × $0. 9397$

$a = \frac{16. 20}{0. 8660}$

a = 18. 7 feet long

Thus, the length of the diagonal and the shorter base are 17. 24 feet and 18. 7 feet long respectively.

Learn more about isosceles trapezoid here:

brainly.com/question/10187910

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5 0

2 years ago

X < -10/3 or x > 2/3

Fittoniya [83]

Hello! :)

Here is a graph for x < -10/3 or x > 2/3.

THEDIPER

6 0

3 years ago

Tri-Star Industries employs electrical, plumbing, and air conditioning technicians. Their home office is made up of three square

Molodets [167]

Answer:

6084 $\text{ft}^2$ .

Step-by-step explanation:

Please find the attachment.

We have been given that the home-office of Tri-star industries is made up of three square buildings, one for each department, with a triangular atrium in the middle. The area of the Plumbing building is 5,184 $\text{ft}^2$ and the area of the A/C building is 900 $\text{ft}^2$ .

We know that area of square is square of its side length. Since all building are squares, so to find the area of electrical building, we will use Pythagoras theorem.

$a^2+b^2=c^2$

We can see from our attachment that side length of electrical building is hypotenuse (c) of the right triangle.

Upon substituting our given information in Pythagoras theorem, we will get:

$5184+900=c^2$

$6084=c^2$

Therefore, the area of electrical building is 6084 square feet.

3 0

3 years ago