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4 years ago

How do I solve 5(4x -5) = 155

1 answer:

5 0

5*(4*x-5)-(155)=0
 5 • (4x - 5) - 155 = 0
 Pull out like factors :
20x - 180 = 20 • (x - 9)
 20 • (x - 9) = 0 Solve : 20 = 0
Solve : x-9 = 0
 Add 9 to both sides of the equation :
 x = 9
hope that helps!!

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The table shows the number of students in a class who play on a school team and/or are members of a school club:

eimsori [14]

This one is very simple.

create a simple equation to find out

15 = 12 + x

subtract 12 from each side

x= 3

the missing number is 3

or, to be even simpler, take the total, subtract the total from the number you know and the difference is the missing number.

hope I helped

ALSO, we can check going down vertically. 3 + 10 =13. this is the total listed at the bottom.

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3 years ago

A professor has eight different tasks to assign, one to each of her eight teaching assistants. In how

insens350 [35]

Answer:

40320

Step-by-step explanation:

There are 8 different people we could assign to the first task. Now there are 7 tasks and 7 people left. There are 7 different people we could assign to the next task. And so on

8 *7*6*5*4*3*2*1

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4 years ago

Find (-3/7) / (-1 1/14). 45/98 2/5 2 1/2 -2/5

RSB [31]

Answer:

option B . $\frac{2}{5}$

Step-by-step explanation:

$(-\frac{3}{7}) \div (-\frac{15}{14}) = (-\frac{3}{7}) \times (-\frac{14}{15}) = \frac{3 \times 14}{7 \times 15} = \frac{2}{5}$

5 0

3 years ago

Read 2 more answers

Three collinear points on the coordinate plane are r(x,y), s(x+8h, y+8k), and p (x+6h, y+6k)

Karo-lina-s [1.5K]

Answer:

A. $\frac{RP}{SP}=3$

B. $\frac{RP}{RS}=\frac{3}{4}$

Step-by-step explanation:

The complete question is

Three collinear points on the coordinate plane are R(x, y), S(x+8h, y+8k), and P(x+6h, y+6k).

Part A: Determine the value of RP/SP

Part B: Determine the value of RP/RS

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$R(x,y),S(x+8h,y+8k) and P(x+6h,y+6k)$

Part A.We have to find the value of $\frac{RP}{SP}$

step 1

Find the distance RP

$R(x,y),P(x+6h,y+6k)$

substitute the values in the formula

$RP=\sqrt{(x+6h-x)^2+(y+6k-y)^2}$

$RP=\sqrt{36h^2+36 k^2}$

$RP=6\sqrt{h^2+k^2}$

step 2

Find the distance SP

$S(x+8h,y+8k),P(x+6h,y+6k)$

substitute the values in the formula

$SP=\sqrt{(x+6h-x-8h)^2+(y+6k-y-8k)^2}$

$SP=\sqrt{4h^2+4k^2}$

$SP=\sqrt{4(h^2+k^2)}$

$SP=2\sqrt{h^2+k^2}$

step 3

Find the ratio RP/SP

$\frac{RP}{SP}=\frac{6\sqrt{h^2+k^2}}{2\sqrt{h^2+k^2}}$

$\frac{RP}{SP}=3$

Part B. We have to determine the value of $\frac{RP}{RS}$

step 1

Find the distance RS

$R(x,y),S(x+8h,y+8k)$

$RS=\sqrt{(x+8h-x)^2+(y+8k-y)^2}$

$RS=\sqrt{64h^2+64k^2}$

$RS=\sqrt{64(h^2+k^2)}$

$RS=8\sqrt{h^2+k^2}$

step 2

Find the ratio RP/RS

$\frac{RP}{RS}=\frac{6\sqrt{h^2+k^2}}{8\sqrt{h^2+k^2}}$

$\frac{RP}{RS}=\frac{3}{4}$

5 0

3 years ago

Help please use photo

damaskus [11]

The domain is the input of the function or n in this case. So, in the boxes, you would put [1, 2, 3, 4, 5, 6, ...]

The range is the output of the function or f(n) in this case. So, in the boxes, you would put [4, 6, 8, 10, 12, 14, ...]

4 0

3 years ago

Read 2 more answers