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egoroff_w [7]
4 years ago
12

A parallel RC circuit has a capacitive reactance of 962 ohms and a resistance of 1,200 ohms what is the impedance of this circui

t
A. 751 ohm
B. 653 ohms
C. 968 ohm
D, 1,254 ohm
Physics
1 answer:
Alex777 [14]4 years ago
6 0

Answer:

<em>A. 751 ohm</em>

Explanation:

Impedance: <em>This is the total opposition to the flow of current in an a.c circuit by any or all of the three circuit elements ( R, L, C). The unit of impedance is Ohms (Ω). The impedance in a parallel circuit is gives a s</em>

<em>Z = RXₐ/√(Xₐ² + R²)............................... Equation 1</em>

<em>Where Z = The impedance of the a.c circuit, Xₐ = capacitive reactance, R = resistance.</em>

<em>Given: Xₐ = 962 Ω, R = 1200 Ω</em>

<em>Substituting these values into equation 1,</em>

<em>Z = 962×1200/√(962² + 1200²)</em>

<em>Z = 1154400/√(925444 + 1440000)</em>

<em>Z = 1154400/√(925444+1440000</em>

<em>Z = 1154400/1538</em>

<em>Z = 750.59 Ω</em>

<em>Z≈ 751 Ω</em>

<em>Therefore the impedance of the circuit = 751 Ω</em>

<em>The right option is A. 751 ohm</em>

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Answer:

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we substitute

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we substitute in the endowment equilibrium equation

     μ (W + W_painter) = cotan θ  (W / 2 + 0,3 W_painter)

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we substitute the values ​​they give

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To finish the problem, we must indicate the angle of the staircase or catcher data to find the angle, if we assume that the angle is tea = 45

       cotan 45 = 1 / tan 45 = 1

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Answer:

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We know that, from Coulomb's law, electric force acting between two charged particles is given as:

F_e=\dfrac{kq_1q_2}{d^2}\\\\Where,k\to Coulomb's\ constant = 9\times 10^9\ N\cdot m^2/C^2

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