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umka21 [38]
3 years ago
12

If It took 40 Seconds for a vehicle of weight 40,000 Newton to move round a 7 metres, What time will it achieve same feat for an

other circular path Of radius 21 metres given the Condition of the vehicle remains the same.​
Physics
1 answer:
Svetllana [295]3 years ago
3 0

Answer:

  t = 376.99 s

Explanation:

We must solve this problem with the equations and kinematics, let's start by looking for the speed of the vehicle,

         v = d / t

         v = 7/40

         v = 0.175 m / s

Since the speed e remains constant, we must find the length of the circle is

          L = 2π r

          L = 2π 21

          L = 131.95 m

In the problem it does not specify clearly, but in general the curves of the road correspond to half a circle, so the length of the road is

         L ’= L / 2

         L ’= 131.95 / 2 = 65.97 m

as the speed is constant

          t = L ’/ v

          t = 65.97 / 0.175

          t = 376.99 s

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Answer:

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Explanation:

When two equal magnitude forces are acting on the rod in opposite direction

Then the net force on the system is always zero in that case

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here we know that

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in all such case object will rotate about a fixed position with change angular speed

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3 years ago
According to recent typical test data, a Ford Focus travels 0.240 mi in 19.3 s, starting from rest. The same car, when braking f
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Answer:

Explanation:

a )

While breaking initial velocity u = 62.5 mph

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= 91.66 ft / s

distance trvelled s = 150 ft

v² = u² - 2as

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b ) While accelerating initial velocity u = 0

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v² = u² + 2as

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4 0
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Answer:

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From the question we have

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We have the final answer as

<h3>3000 N</h3>

Hope this helps you

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