Answer:
n=5
Step-by-step explanation: happy to hlp
Denote by
the random variables representing the integer values
, respectively. Then
and
, where
denotes the discrete uniform distribution over the interval
. So
and
have probability mass functions


We want to find
, where
is any integer.
We have six possible choices for
:
(i) if
, then
is an integer when
;
(ii) if
, then
is an integer when
;
(iii) if
, then
is an integer when
;
(iv) if
, then
is an integer when
;
(v) if
or
, then
is an integer only when
in both cases.
If the selection of
are made independently, then the joint distribution is the product of the marginal distribution, i.e.
![p_{R,K}(r,k)=p_R(r)\cdot p_K(k)=\begin{cases}\dfrac1{48}&\text{for }(r,k)\in[-2,5]\times[2,7]\\\\0&\text{otherwise}\end{cases}](https://tex.z-dn.net/?f=p_%7BR%2CK%7D%28r%2Ck%29%3Dp_R%28r%29%5Ccdot%20p_K%28k%29%3D%5Cbegin%7Bcases%7D%5Cdfrac1%7B48%7D%26%5Ctext%7Bfor%20%7D%28r%2Ck%29%5Cin%5B-2%2C5%5D%5Ctimes%5B2%2C7%5D%5C%5C%5C%5C0%26%5Ctext%7Botherwise%7D%5Cend%7Bcases%7D)
That is, there are 48 possible events in the sample space. We counted 12 possible outcomes in which
is an integer, so the probability of this happening is
.
Answer:
-18*5 is you answer aka -90
Answer:
The smaller number is 11
Step-by-step explanation:
The question is
One number is 3 less than a second number. Twice the second number is 16 less than 4 times the first. Find the smaller of two numbers
Let
x and y the numbers
x=y-3 ----> equation A
2y=4x-16 ----> equation B
Substitute equation A in equation B and solve for y
2y=4(y-3)-16
2y=4y-12-16
4y-2y=12+16
2y=28
y=14
x=14-3=11
9514 1404 393
Answer:
- vertical scale ×2; translate (-1, -5); (-1, -5), (0, -3), (-2, -3)
- vertical scale ×1/2; translate (3, 1); (3, 1), (1, 3), (5, 3)
- reflect over x; vertical scale ×2; translate (-3, -4); (-3, -4), (-2, -6), (1, -8)
Step-by-step explanation:
Transformation of parent function f(x) into g(x) = c·f(x-h)+k is a vertical scaling by a factor of c, and translation by (h, k) units to the right and up. If c is negative, then a reflection over the x-axis is also part of the transformation. Once you identify the parent function (here: x² or √x), it is a relatively simple matter to read the values of c, h, k from the equation and list the transformations those values represent.
For most functions, points differing from the vertex by 1 or 2 units are usually easily found. Of course, the vertex is one of the points on the function.
<h3>1.</h3>
(c, h, k) = (2, -1, -5)
- vertical scaling by a factor of 2
- translation 1 left and down 5
Points: (-1, -5), (-2, -3), (0, -3)
__
<h3>2.</h3>
(c, h, k) = (1/2, 3, 1)
- vertical scaling by a factor of 1/2
- translation 3 right and 1 up
Points: (3, 1), (1, 3), (5, 3)
__
<h3>3.</h3>
(c, h, k) = (-2, -3, -4)
- reflection over the x-axis
- vertical scaling by a factor of 2
- translation 3 left and 4 down
Points: (-3, -4), (-2, -6), (1, -8)
_____
<em>Additional comment</em>
For finding points on the parabolas, we use our knowledge of squares and roots:
1² = 1, 2² = 4
√1 = 1, √4 = 2