So first we factor
9-t^2=difference of 2 perfect squares
a^2-b^2=(a-b)(a+b)
3^2-t^2=(3-t)(3+t)
t^2+t-12
factor by finding what 2 number add to get 1 and multiply to get -12
the numbers are -3 and 4
(t-3)(t+4)
[(3-t)(3+t)]/[(t-3)(t+4)] we can't factor out any further
if it was t^2-9 then we could go further but since it isn't this is the factored form
(<u><em>if</em></u> it was t^-9 then the answer would be (t+3)/(t+4))
Answer:C
Step-by-step explanation:
If you work out the difference between 2 and 7 you will get 4 so you add 4 each time.
3=12
4=16
5=20
Answer:
Step-by-step explanation:
If all had been children's tickets, revenue would have been $925. Actual revenue is $1150 -925 = $225 more than that. Changing a child's ticket to an adult's ticket add $1 to the revenue, so there must be $225 such changes.
The number of adult tickets is 225; the number of children's tickets is 925-225 = 700.
Answer:
y=-6x+33
Step-by-step explanation:
Perpendicular lines meet the following condition:
m1*m2=-1
From the first line equation, we obtain m1 if we write the given equation in a proper manner. 6y=x-12 becomes y=x/6 -12,
m1=1/6 since is the coefficient of 'x' variable.
Now, to obtain 'm2' we use the condition for perpendicular lines
(1/6)*m2=-1
m2=-6
Thus, our new line have an equation like the following y=mx+b, where m=-6
Now, we need to eval the given point (6,-3) in the equation in from above to obtain the value of 'b'
-3= -6*(6) + b
Leading us to, b=33
