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3 years ago

CHILL OUT WITH THE "ASAP" "HURRY" "PLEASEEEEEEEE" I'M GETTING TO AS MANY AS I CAN

Mathematics

2 answers:

Katarina [22]3 years ago

5 0

Answer:

nope

Step-by-step explanation:

finlep [7]3 years ago

3 0

Answer:

1120479037157389478073281965092374871290432

Step-by-step explanation:

have a great day

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(01.03 MC) Traveling at 65 miles per hour, how many minutes, rounded to the nearest whole number, does it take to drive 125 mile

mariarad [96]

It should take 115 minutes

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3 years ago

Will mark as brainliest please help.

alex41 [277]

The first one is the answer to the first question.

the second one is the answer to the second question

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25 POINTS I WILL GIVE BRAINLIEST Patty’s Parasols recorded the monthly rainfall and their umbrella sales for an entire year. The

Deffense [45]

Answer:

a) From the chart crated with Microsoft Excel, we have that the correlation coefficient, r = √0.8581 ≈ 0.93 to the nearest hundredth

The steps used includes

1) Inputting the given data into the cells on a Microsoft Excel spread sheet

2) Highlighting and sorting the data in the cells in order of increasing Rainfall

3) Generating a dot plot using the sorted data from above

4) Adding the trend line, Square of the linear regression, and the trend line equation

5) Adding the axis labels

(b) The correlation coefficient states that there is a strong positive correlation between the monthly rainfall and and Umbrella sales

Step-by-step explanation:

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3 years ago

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What is Limit of StartFraction StartRoot x + 1 EndRoot minus 2 Over x minus 3 EndFraction as x approaches 3?

scoray [572]

Answer:

$\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} = \boxed{ \frac{1}{4} }$

General Formulas and Concepts:

Calculus

Limits

Limit Rule [Variable Direct Substitution]:
$\displaystyle \lim_{x \to c} x = c$

Special Limit Rule [L’Hopital’s Rule]:
$\displaystyle \lim_{x \to c} \frac{f(x)}{g(x)} = \lim_{x \to c} \frac{f'(x)}{g'(x)}$

Differentiation

Derivatives
Derivative Notation

Derivative Property [Addition/Subtraction]:
$\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$
Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:
$\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

Identify given limit.

$\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3}$

Step 2: Find Limit

Let's start out by directly evaluating the limit:

[Limit] Apply Limit Rule [Variable Direct Substitution]:
$\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} = \frac{\sqrt{3 + 1} - 2}{3 - 3}$
Evaluate:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \frac{\sqrt{3 + 1} - 2}{3 - 3} \\& = \frac{0}{0} \leftarrow \\\end{aligned}$

When we do evaluate the limit directly, we end up with an indeterminant form. We can now use L' Hopital's Rule to simply the limit:

[Limit] Apply Limit Rule [L' Hopital's Rule]:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\\end{aligned}$
[Limit] Differentiate [Derivative Rules and Properties]:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \leftarrow \\\end{aligned}$
[Limit] Apply Limit Rule [Variable Direct Substitution]:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \\& = \frac{1}{2\sqrt{3 + 1}} \leftarrow \\\end{aligned}$
Evaluate:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \\& = \frac{1}{2\sqrt{3 + 1}} \\& = \boxed{ \frac{1}{4} } \\\end{aligned}$

∴ we have evaluated the given limit.

___

Learn more about limits: brainly.com/question/27807253

Learn more about Calculus: brainly.com/question/27805589

___

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

3 0

2 years ago

2% of 350 is what number?

weeeeeb [17]

Answer:

Step-by-step explanation:

An easy way to find any percentage of a number is to multiply with decimals. To do this you have to first convert the percentage to a decimal. Do this by moving the decimal point in the percentage 2 places to the left. This means that 2.0% becomes 0.02. Then, multiply this decimal by the whole number. So, 0.02*350. This equals 7, which is 2% of 350.

This same trick will work with any problem. For example 38% of 435 is the same as 0.38*435, which equals 165.3.

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3 years ago

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