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Natalka [10]
3 years ago
14

You're going to be mowing lawns as a summer job. How long will it take for your

Computers and Technology
1 answer:
ahrayia [7]3 years ago
8 0
Hshshshhshshs 3. 4 hours
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Why don't we get together to watch the Academy Awards?
Step2247 [10]

Answer:

idk I'm not sure cause yeah

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To add color to the entire background of a page, users will select the ___ feature?
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The Fill color tab. Hope this helps!
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Triangle O N M is cut by line segment L K. Line segment L K goes from side N O to side N M. The length of N L is x, the length o
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D) x=8

Explanation:

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Write a program in python that reads an unspecified number of integers from the user, determines how many positive and negative
blondinia [14]

Answer:

count_p = 0

count_n = 0

total = 0

while True:

   number = int(input("Enter an integer, the input ends if it is 0: "))

   if number == 0:

       break

   else:

       total += number

       if number > 0:

           count_p += 1

       elif number < 0:

           count_n += 1

print("The number of positives is: " + str(count_p))

print("The number of negatives is: " + str(count_n))

print("The total is: " + str(total))

print("The average is: " + str(total / (count_p + count_n)))

Explanation:

Initialize the variables, count_p represens the number of positives, count_n represents the number of negatives, and total represents the total of the numbers

Create a while loop iterates until the user enters 0. If the number is not 0, then add it to the total. If the number is greater than 0, increase count_p by 1. If the number is smaller than 0, increase count_n by 1.

When the loop is done, print the count_p, count_n, total, and average

6 0
3 years ago
computer has a 32-bit instruction word broken into fields as follows: opcode, six bits; two register file address fields, five b
lina2011 [118]

Answer:

a.  2^6, or 64 opcodes.

b.  2^5, or 32 registers.

c. 2^16, or 0 to 65536.

d.  -32768 to 32768.

Explanation:

a. Following that the opcode is 6 bits, it is generally known that the maximum number of opcodes should be 2^6, or 64 opcodes.

b. Now, since the size of the register field is 5 bits, we know that 2^5 registers can be accessed, or 32 registers.

c. Unsigned immediate operand applies to the plus/minus sign of the number. Since unsigned numbers are always positive, the range is from 0 to 2^16, or 0 to 65536.

d. Considering that the signed operands can be negative, they need a 16'th bit for the sign and 15 bits for the number. This means there are 2 * (2^15) numbers, or 2^16. However, the numbers range from -32768 to 32768.

6 0
3 years ago
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