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anzhelika [568]
3 years ago
15

Identify the parts of the energy diagrams.

Physics
1 answer:
Usimov [2.4K]3 years ago
3 0
This might help, but otherwise, I'm not sure what you mean.

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The horizontal bar rises at a constant rate of three hundred mm/s causing peg P to ride in the quarter circular slot. When coord
SVETLANKA909090 [29]

Answer:

Explanation:

Given

Horizontal bar rises with 300 mm/s

Let us take the horizontal component of P be

P_x=rcos\theta

P_y=rsin\theta

where \thetais angle made by horizontal bar with x axis

Velocity at y=150 mm

150=300sin\theta

thus \theta =30^{\circ}

position ofP_x=rcos\theta =300\cdot cos30=300\times \frac{\sqrt{3}}{2}

P_x=259.80 mm

P=259.80\hat{i}+150\hat{j}

Velocity at this instant

u_x=-rsin\theta =300\times sin30=-150 mm/s

u_y=rcos\theta =300\times cos30=259.80 mm/s

4 0
3 years ago
Which two conditions explain why special technology is required to study the
enot [183]

Answer:

A. Extremely high pressure

5 0
2 years ago
Read 2 more answers
What is the acceleration of a car moving
Iteru [2.4K]

Answer: Accelaration is 2.77 m/s*s

<h2 />

Explanation:

V0=0km/h=0m/s

V1=100 km/h=27.7 m/s

t=10s=

Use equation for accelaration : a=(V1-V0)/t

a=(0m/s-27.7m/s)/10s

a=-27.7s/10s

a=2.77m/s*s

6 0
4 years ago
A 95 N force exerted at the end of a 0.50 m long torque wrench gives rise to a torque of 15 N · m. What is the angle (assumed to
o-na [289]

Answer:

angle = 18.40 degree

Explanation:

given data

force = 95 N

distance = 0.50 m

torque = 15 N · m

to find out

angle between the wrench handle and the direction of the applied force

solution

we will apply here torque equation that is express as

torque =  distance × force × sin(θ)   ...................1

put here value we will get angle that is

15 = 0.50 × 95 × sin(θ)

sin(θ) = 0.315789

θ = 18.40 degree

6 0
3 years ago
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Astronaut mark uri is space-traveling from planet x to planet y at a speed of relative to the planets, which are at rest relativ
lyudmila [28]
<span>From the point of view of the astronaut, he travels between planets with a speed of 0.6c. His distance between the planets is less than the other bodies around him and so by applying Lorentz factor, we have 2*</span>√1-0.6² = 1.6 light hours. On the other hand, from the point of view of the other bodies, time for them is slower. For the bodies, they have to wait for about 1/0.6 = 1.67 light hours while for him it is 1/(0.8) = 1.25 light hours. The remaining distance for the astronaut would be 1.67 - 1.25 = 0.42 light hours. And then, light travels in all frames and so the astronaut will see that the flash from the second planet after 0.42 light hours and from the 1.25 light hours is, 1.25 - 0.42 = 0.83 light hours or 49.8 minutes.
5 0
3 years ago
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