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Tpy6a [65]
4 years ago
11

What is the equilibrium line of a glacier?

Physics
1 answer:
drek231 [11]4 years ago
8 0
The equilibrium line<span> separates the ablation zone and the accumulation zone; it is the altitude where the amount of new snow gained by accumulation is equal to the amount of ice lost through ablation. The upper part of a </span>glacier<span>, where accumulation exceeds ablation, is called the accumulation zone.</span>
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A uniform metal bar 100cm long balances at 20cm mark when a mass of 1.5kg is attached at 0cm mark calculate the weight of the ba
beks73 [17]

Answer:

30 N

Explanation:

there are two forces act on the bar:

- weight of 1.5 kg mass, w = mg = 15 N

- weight of the bar, wb

for balance,

w * Lw = wb * Lwb

Lw = length of bar from the mass to the pivot

Lwb = lenght of bar from the center of the bar to the pivot

15 * 20 = wb * (50-20)

300 = wb * 30

wb = 300/30 = 30 N

4 0
4 years ago
Find the magnitude of the impulse delivered to a soccer ball when a player kicks it with a force of 1450 N . Assume that the pla
juin [17]

To solve this problem we will apply the concept of Impulse. Which is described as the product between the Force and the change in time. Mathematically this can be described as

I = F \Delta t

Where,

F = Force

\Delta t= Time

Our values are given as,

F = 1450N

\Delta t = 5.1*10^{-3} s

Replacing we have,

I = (1450)(5.1*10^{-3})

I = 7.395Kg\cdot m/s

Therefore the impulse delivered to the soccer ball is 7.395Kg\cdot m/s or  7.395N\cdot s

4 0
3 years ago
Even at such low fractions of the speed of light these stars are moving quite quickly (thousands of kilometers a second) compare
yulyashka [42]
According to Doppler Effect, an observer at rest will perceive a shift in the wavelength or frequency of the radiation emitted by a source in movement.This shift is given by the formula:
\frac{ \lambda - \lambda_{0} }{ \lambda_{0} } = \frac{-v}{c}

where:
\lambda = observed wavelength
\lambda_{0} = wavelength at rest
v = speed of source (positive if towards the observer, negative if away from the observer)
c = speed of light

Therefore, we can solve for the observed wavelength:
\lambda = \lambda_{0} (\frac{-v}{c}) + \lambda_{0} \\ \lambda = \lambda_{0} (1 - \frac{v}{c})

Substituting the given data:
\lambda = 656.46 (1 - \frac{300}{299792})
= 655.80 nm

Hence, the observed wavelength of the line would be 655.80 nm. Note that this value is smaller than the one at rest, which means that we have a blue-shift, as expected for an approaching source.
5 0
3 years ago
Find the sum. Express the answer in scientific notation.<br> (1.54 x 10^6)+(6.15 x 10°)
klasskru [66]

ans will be 1500006.15

= 1.5*10^6

we move the decimal point to the left six digits

8 0
3 years ago
A 1.6-cm-thick wood floor covers a 4.0m×5.5m room. Part A The subfloor on which the flooring sits is at a temperature of 16.1 ∘C
Bogdan [553]

Answer:

Rate of heat conduction will be 935 Watt

Explanation:

We have given thickness of the floor d = 1.6 cm = 0.016 m

Area A=4\times 5.5=22m^2

Temperature difference \Delta T=19.5-16.1=3.4^{\circ}C

Thermal conductivity of the wood k = 0.200 w/M-K

We have to find heat conduction

Heat conduction is given by \frac{Q}{t}=\frac{kA\Delta T}{d}=\frac{0.200\times 22\times 3.4}{0.016}=935Watt

Rate of heat conduction will be 935 Watt

3 0
4 years ago
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