Answer:
5.33*10^-3 seconds
Explanation:
c = d/t
c = speed of light constant (3.0*10^5 km/s)
d = distance (1600 km)
t = ?
3.0*10^5 = 1600/t
t = 1600/3.0*10^5
t = 5.33*10^-3 seconds
I hope this helped! :)
Copernicus preferred the heliocentric model.
Answer:
c) 0.16 m/s2
Explanation:
The computation of the acceleration during the first km of travel is shown below
Given that
Final velocity = v = 42 m/s
Initial velocity = u = 0 m/s
Distance = 5.6km
Based on the above information, we need to apply the following formula
As we know that



= 0.1575 m/s ^2
hence, the correct option is c. 0.16 m.s^2
<span>as i recall, gravity is relative to the square of the distance.
so if the distance is tripled, then the gravitational attraction would be reduced by 3^2 or 1/9.
so F1 = F0/9
if the satellite is 2R from the center, and is moved to 4R (doubled would be 3R, tripled is 4R) then the distance is twice, and gravity would be 2^2 or 1/4.
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