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horrorfan [7]
3 years ago
11

Two circular loops of wire, each containing a single turn, have the same radius of 3.40 cm and a common center. The planes of th

e loops are perpendicular. Each carries a current of 1.80 A. What is the magnitude of the net magnetic field at the common center?
Physics
1 answer:
Shkiper50 [21]3 years ago
4 0

Answer: To solve for the net magnetic field of two circular loops of wire, each containing a single turn

B net= √[( NUI / 2R)^2 × ( NUI / 2R)^2]

Where B net = Net magnetic field

B net = √2 × (NUI/ 2R)

B net =[ √2 × 1 × ( 4 × 3.142 × 10^-7) × (1.8)] ÷ 2 × 0.034

B net = { 1.414 × (0.00000126) × (1.8)}÷ 0.068

B net = 4.72 × 10^-5 T

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2 years ago
An elevator filled with passengers has a mass of 1603 kg. (a) The elevator accelerates upward from rest at a rate of 1.20 m/s2 f
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Answer:

T = 17649.03 N = 17.65 KN

Explanation:

The tension in the cable must be equal to the apparent weight of the passenger. For upward acceleration:

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8 0
3 years ago
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D. Velocity because it describes a speed and direction
6 0
4 years ago
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Study the following reaction carefully. What classification should this reaction have?
Mariulka [41]

Answer:

Synthesis reaction

Explanation:

Synthesis reaction: two or more compounds combine to form one.

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Decomposition reaction: one compound forms two or more.

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A load of 1 kW takes a current of 5 A from a 230 V supply. Calculate the power factor.
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Power factor = 0.87 (Approx)

Explanation:

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Power factor = watts / (V)(I)

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Power factor = 1,000 / (1,150)

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