During feasting, there is an increase in the supply of carbohydrates, fats and proteins in the body. Since these macronutrients are in excess, carbohydrates and proteins are utilized or oxidized as a source for energy production. On the otherhand, fats are accumulated as the rate of oxidation of this source does not increase during feasting.
Answer:
Flora and Fauna
Explanation:
therethere are four main regions which are each home to specific landforms, flora and fauna the. These are the upland, the Everglades, the Florida Keys and the Gulf Coast
Answer:
Rate expression has been given below
Explanation:
According to the given equation, 1 molecule of A reacts with 1 molecule of B and produces 2 molecules of B at a time.
So, rate of disappearance of both A and B are one half of rate of appearance of B
Hence rate expression can be represented as:
![Rate=\frac{-\Delta [A]}{\Delta t}=\frac{-\Delta [B]}{\Delta t}=\frac{1}{2}\frac{\Delta [C]}{\Delta t}](https://tex.z-dn.net/?f=Rate%3D%5Cfrac%7B-%5CDelta%20%5BA%5D%7D%7B%5CDelta%20t%7D%3D%5Cfrac%7B-%5CDelta%20%5BB%5D%7D%7B%5CDelta%20t%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7B%5CDelta%20%5BC%5D%7D%7B%5CDelta%20t%7D)
where ![\frac{-\Delta [A]}{\Delta t}](https://tex.z-dn.net/?f=%5Cfrac%7B-%5CDelta%20%5BA%5D%7D%7B%5CDelta%20t%7D)
is rate of disappearance of A, ![\frac{-\Delta [B]}{\Delta t}](https://tex.z-dn.net/?f=%5Cfrac%7B-%5CDelta%20%5BB%5D%7D%7B%5CDelta%20t%7D)
is rate of disappearance of B and ![\frac{\Delta [C]}{\Delta t}](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20%5BC%5D%7D%7B%5CDelta%20t%7D)
rate of appearance of C
Thus 174 protons would make at most 6 copper atoms. However, it would take 174 extra electrons (29 per atom) and even more neutrons than that to construct neutral copper atoms with stable nuclei.
The equation is:
Ca(OH)₂(s) + 2 HCl(aq) → CaCl₂(aq) + 2 H₂<span>O(l)
</span>
n=mass in g/M.M
15 g Ca(OH)₂ is n=15 g/ 74.1 g/mol=0.2024 mol of Ca(OH)₂
no. of mol of HCl:
n=0.5 mol/L*0.075L=0.0375 mol
This could react with 0.0375/2= 0.01875 mol of Ca(OH)₂ We have a lot more than that.
Therefore, HCl is the limiting reagent and determines how much CaCl₂ forms.
Based on the balanced reaction, 2 moles of HCl gives 1 mole of CaCl₂
no. of mol of CaCl₂= 0.0375/2= 0.01875 mol
mass in g=n*MM= 0.01875*111= 2.08 g
