All categories

3 years ago

Please help me in answering these questions

Chemistry

1 answer:

ki77a [65]3 years ago

7 0

Answer:

which answer questions hi to nhi hai

You might be interested in

Which measure of a gas does the expression

Usimov [2.4K]

Answer:

A. volume

Explanation:

Generally the equation for the ideal gas is mathematically given as

PV=nRT

Where

P=pressure

V=volume

R=gas constant

n=Number of Moles

T=Temperature

Therefore

V=nRT/P

Option A

For more information on this visit

brainly.com/question/17756498

7 0

2 years ago

What is the frequency of a wave with a wavelength of 6.40x10^4 meters?

yKpoI14uk [10]

Answer:

frequency = 0.47×10⁴ Hz

Explanation:

Given data:

Wavelength of wave = 6.4× 10⁴ m

Frequency of wave = ?

Solution:

Formula:

Speed of wave = wavelength × frequency

Speed of wave = 3 × 10⁸ m/s

Now we will put the values in formula.

3 × 10⁸ m/s = 6.4× 10⁴ m × frequency

frequency = 3 × 10⁸ m/s / 6.4× 10⁴ m

frequency = 0.47×10⁴ /s

s⁻¹ = Hz

frequency = 0.47×10⁴ Hz

Thus the wave with wavelength of 6.4× 10⁴ m have 0.47×10⁴ Hz frequency.

4 0

3 years ago

Read 2 more answers

Need help asappp please

Jet001 [13]

Answer:

<h2>C.POLAR</h2>

Explanation:

According to research :

Methanol is a polar molecule:

The alcohol (-OH) group dominates the molecule making it definitely polar.

8 0

3 years ago

Yesterday I drove 150 minutes at a speed of 100 miles/hr. How many miles did I drive?

katrin [286]

That’s 2.5 hours at 100 miles an hour
2.5•100=250
You drove 250 mi yesterday

6 0

2 years ago

Calculate the number of pounds of CO2CO2 released into the atmosphere when a 22.0 gallon22.0 gallon tank of gasoline is burned i

Gnesinka [82]

Answer:

391.28771 pounds of carbon-dioxide was released into the atmosphere when 22.0 gallon tank of gasoline is burned in an automobile engine.

Explanation:

Density of the gasoline ,d= 0.692 g/mL

Volume of gasoline in an tanks,V = 22.0 gallons = 83,279.02 mL

Let mass of the gasoline be M

$Density= \frac{Mass}{Volume}$

M = V × d = 83,279.02 mL × 0.692 g/mL=57,629.081 g

Given that gasoline is primarily octane.

$2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O$

Mass of octane burnt in the tank = M = 57,629.081 g

Moles of octane = $\frac{57,629.081 g}{114.08g/mol}=505.1637 mol$

According to reaction, 2 moles of octane gives 16 moles of carbon-dioxide.

Then 505.1637 mol of octane will give:

$\frac{16}{2}\times 505.1637 mol=4,041.3100 mol$ of carbon-dioxide

Mass of 4,041.3100 mol of carbon-dioxide:

4,041.3100 mol × 44.01 g/mol = 177,858.05 g

Mass of carbon-dioxide produced in pounds = 391.28771 pounds

391.28771 pounds of carbon-dioxide was released into the atmosphere when 22.0 gallon tank of gasoline is burned in an automobile engine.

3 0

3 years ago