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3 years ago

What does scientific inquiry refer to

Chemistry

1 answer:

Sloan [31]3 years ago

5 0

It refers to the ways scientists explore and study the world based on observations and their works/ evidence.

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How many grams of hcl can dissolve in 200 g of water at 60 c?

Eddi Din [679]

The solubility curve is a plot of solubility against temperature.

<h3>What is solubility?</h3>

The term solubility refers to the amount of substance that dissolves in solution at a given temperature. Hence, the solubility curve is a plot of solubility against temperature.

Thus, from the solubility curve (not shown) the amount if HCl dissolved can be obtained hence the question is incomplete.

Learn more about solubility:brainly.com/question/8591226

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8 0

2 years ago

Clouds that form at an elevation of 3 kilometers will

nordsb [41]

A.) Raindrops I believe

3 0

3 years ago

What is the ratio of the concentration of sodium acetate to the concentration of acetic acid at ph 5.75?

GREYUIT [131]

To get the ratio of the concentration of sodium acetate to the concentration of acetic acid we are going to use H-H equation:

when:

PH = Pka + ㏒[salt/acid]

when the Ka of acetic acid = 1.75 x 10^-5

so, we can get Pka from this formula:

Pka = -㏒Ka

= -㏒1.75 x 10^-5

= 4.76

and when we have PH = 5.75, so by substitution:

∴ 5.75 = 4.76 + ㏒[acetate/ acetic acid]

∴ [acetate/acetic acid] = 9.77

∴ the ratio of a concentration of acetate to acetic acid 9.77

4 0

3 years ago

Can someone solve this plz<br> βeta decay<br> carbon atomic mass 14 <br> atomic # 6

nordsb [41]

Answer:

14/6C your welcome

Explanation:

8 0

3 years ago

A water treatment plant has 4 settling tanks that operate in parallel (the flow gets split into 4 equal flow streams), and each

ale4655 [162]

Answer:

a) When the 4 tanks operate in parallel the retention time is 1.26 hours.

b) If the tanks are in series, the retention time would be 0.31 hours

Explanation:

The plant has 4 tanks, each tank has a volume V = 600 $m_3$ . The total flow to the plant is Ft = 12 MGD (Millions of gallons per day)

When we use the tanks in parallel, it means that the total flow will be divided in the total number of tanks. F1 will be the flow of each tank.

Firstly, we should convert the MGD to $m_3 /day$ . In that sense, we can calculate the retention time using the tank volume in $m_3$ .

$Ft =12 \frac{MG}{day} (\frac{1*10^6 gall}{1MG} ) (\frac{3.78 L}{1 gall} ) (\frac{1 dm^3}{1L} ) (\frac{1 m^3}{10^3 dm^3} ) = 45360 \frac{m^3}{day}$

After that, we should divide the total flow by four, because we have four tanks.

$F1 = Ft/4 =(45360 \frac{m^3}{d} )/4 = 11 340 \frac{m^3}{d}$

To calculate the retention time we divide the total volume V by the flow of each tank F1.

$t1 =\frac{V1}{F1} = \frac{600 m^3}{11340 \frac{m^3}{d} } = 0.0529 day\\t1 = 0.0529 d (\frac{24 h}{1d} ) = 1.26 h$

After converting t1 to hours we found that the retention time when the four reactors are in parallel is 1.26 hours.

If the four reactors were working in series, the entire flow goes first through one tank, then the second and so on. It means the total flow will be the flow of each tank.

In that order of ideas, the flow for reactors in series will be F2, and will have the same value of F0.

F2 = F0

To calculate the retention time t2 we divide the total volume V by the flow of each tank F2.

$t2 =\frac{V1}{F2} = \frac{600 m^3}{45360 \frac{m^3}{d} } = 0.01 day\\t2 = 0.01 d (\frac{24 h}{1d} ) = 0.31 h$

After converting t2 to hours we found that the retention time when the four reactors are in series is 0.31 hours.

5 0

3 years ago