Answer:
Average atomic mass = 63.553 amu.
Explanation:
Given data:
Abundance of Y-63 = 69.17%
Abundance of Y-65 = 100 - 69.17 = 30.83%
Atomic mass of Y-63 = 62.940 amu
Atomic mass of Y-65 = 64.928 amu
Atomic mass of Y = ?
Solution:
Average atomic mass= (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass= (62.940×69.17)+(64.928×30.83) /100
Average atomic mass = 4353.560 + 2001.730 / 100
Average atomic mass = 6355.29 / 100
Average atomic mass = 63.553 amu.
Answer:
Explanation:
Word equation:
sulfuric acid + ammonium hydroxide → ammonium sulfate + water
Chemical equation:
H₂SO₄ + NH₄OH → (NH₄)₂SO₄ + H₂O
Balanced chemical equation:
H₂SO₄ + 2NH₄OH → (NH₄)₂SO₄ + 2H₂O
The given reaction is the reaction of acid with base. When acid and base react salt and water are produced. In given reaction an acid sulfuric acid and base ammonium hydroxide react and form ammonium sulfate salt and water. The given reaction also follow the law of conservation of mass.
Steps to balance the equation:
Steps 1;
H₂SO₄ + NH₄OH → (NH₄)₂SO₄ + H₂O
H = 7 H = 10
S = 1 S = 1
O = 5 O = 5
N = 1 N = 2
Step 2:
H₂SO₄ + 2NH₄OH → (NH₄)₂SO₄ + H₂O
H = 12 H = 10
S = 1 S = 1
O = 6 O = 5
N = 2 N = 2
Step 3:
H₂SO₄ + 2NH₄OH → (NH₄)₂SO₄ + 2H₂O
H = 12 H = 12
S = 1 S = 1
O = 6 O = 6
N = 2 N = 2
40.28 sorry if it is wrong:) but I tried
Answer:
2–methylpropene.
Explanation:
To successfully name the compound given in the question, we must observe the following:
1. Determine the functional group of the compound.
2. Locate the longest continuous carbon chain. This gives the parent name of the compound.
3. Identify the substituent group attached and locate it's position by giving it the lowest possible count.
4. Combine the above to obtain the name of the compound.
Now, let us determine the name of the compound. This is illustrated below:
1. The functional group of the compound is the double bond i.e the compound is an alkene.
2. The longest continuous carbon chain is 3 i.e propene since it is an alkene.
3. The substituent group attached is methyl i.e CH3. In this case, we'll start counting from the side of the double bond being the functional group. Therefore, the methyl group i.e CH3 is at carbon 2.
4. Therefore, the name of the compound is:
2–methylpropene
The molecular formula of a compound that has 6 carbon, 8 hydrogen, and 2 oxygen will be c6h8o2
