Answer:
b. 485 kPa
Explanation:
Gay-Lussac's law express that the pressure of a gas under constant volume is directly proportional to the absolute temperature. The equation is:
P1T2 = P2T1
<em>P is pressure and T absolute temperature of 1, initial state and 2, final state of the gas</em>
<em>Where P1 = 74psi</em>
<em>T2 = 20°C + 273.15 = 293.15K</em>
<em>P2 = ?</em>
<em>T1 = (95°F -32) * 5/9 + 273.15 = 308.15K</em>
<em />
Replacing:
74psi*293.15K = P2*308.15K
70.4psi
In kPa:
70.4psi * (6.895kPa / 1psi) =
<h3>b. 485 kPa
</h3>
Answer:
CH3OH + 02 ----> C02 + H20
balanced equation -
CH3OH + 3/202 ----> C02 + 2H20
Use exactly the same process as the one used on another question of yours I answered.
Naming conventions for 2 non-metals like Si and O are based on their valence electrons, Si has 4 electrons around it and Oxygen has 6, in order for you to satisfy octet (8 electrons around each element) surrounding each Si and O, you need another O, To name these 2, just write the name of the first element which has less electrons first then the second element to which you use a prefix "di" since it means there are two oxygen, then put the names together and end the name of the second element with "ide" (remove the last 4 letters).
Silicon + "dI" + ox +"ide"
