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nordsb [41]
3 years ago
11

Nstantaneous speed is measured _____. A. At a particular point in time B. Before the object begins to move C. Over the duration

of a trip D. While the object is slowing down
Physics
2 answers:
Vinvika [58]3 years ago
7 0

Answer:

. At a particular point in time.

Explanation:

Instantaneous velocity is the velocity of an object in motion at a specific point in time. This is determined similarly to average velocity, but we narrow the period of time so that it approaches zero. If an object has a standard velocity over a period of time, its average and instantaneous velocities may be the same. Instantaneous speed is the magnitude of instantaneous velocity

erik [133]3 years ago
4 0

Answer:

A. At a particular point in time

Explanation:

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A 2290 kg car traveling at 10.5 m/s collides with a 2780 kg car that is initially at rest at the stoplight. The cars stick toget
avanturin [10]

Answer:

0.41

Explanation:

given,

mass of the car, m = 2290 Kg

initial speed = 10.5 m/s

mass of another car, M = 2780 Kg

distance moved = 2.80 m

coefficient of friction = ?

conservation of energy

m u = (M + m) V

2290 x 10.5 = (2290 + 2780) V

V = 4.74 m/s

using equation of motion

v² = u² + 2 a s

4.74² = 2 x a x 2.8

a = 4.02 m/s²

now using equation

a = μ g

4.02 = μ x 9.8

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3 years ago
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3 years ago
PLEASE HELP: Which of the following procedures describes how you could best test the hypothesis that a crumpled piece of paper f
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Answer:

A because it is the most affective way to do it

Explanation:

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3 years ago
What is the minimum body mass index for obesity
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3 years ago
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A small, single engine airplane is about to take off. The airplane becomes airborne, when its speed reaches 161.0 kmph. The cond
lukranit [14]

Answer:

384.6 m

Explanation:

The length of the runway airport should be long enough to accommodate the aircraft during its acceleration from rest to 161 km/h at rate of 2.6 m/s. We can use the following equation of motion to solve for this:

v^2 - v_0^2 = 2a\Delta s

where v0 = 0 m/s is the initial velocity of the airplane when it start accelerating, v = 161 km/h = 161*1000*(1/60)(1/60) = 44.72 m/s is the airborn speed, a = 2.6 m/s2 is the acceleration, and \Delta s is the distance of the runway, which we care looking for

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