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dexar [7]
3 years ago
8

An ideal gas is enclosed in a piston, and 1600 J of work is done on the gas. As this happens, the internal energy of the gas inc

reases by only 500 J. During this process, how much heat flows into or out of the ideal gas? Enter a positive number to indicate a heat flow into the gas or a negative number to indicate a heat flow out of the gas.
Physics
1 answer:
Phantasy [73]3 years ago
3 0

Answer:

- 1100 J heat flows out

Explanation:

dW = - 1600 J (as work is done on the gas)

dU = 500 J

dQ = ?

According to the first law of thermodynamics

dQ = dU + dW

dQ = 500 - 1600

dQ = - 1100 J

As heat is negative so it flows out.

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Answer:

The work flow required by the compressor = 100.67Kj/kg

Explanation:

The solution to this question is obtained from the energy balance where the initial and final specific internal energies and enthalpies are taken from A-17 table from the given temperatures using interpolation .

The work flow can be determined using the equation:

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Workflow = P2alpha2 - P1alpha1

Workflow = (h2 -U2) - (h1 - U1)

Workflow = ( 684.344 - 491.153) - ( 322.483 - 229.964)

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The acceleration goes up.
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Which of the following lists the stars in order from least density to greatest density?
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when you strike two tuning forks simultaneously you hear three beats per second. the frequency of the first tuning fork is 440 h
s344n2d4d5 [400]

Answer:

We have two possible values for the second tuning fork

443Hz and 337Hz

Explanation:

When two waves of slightly different frequency interfere, they produce beats and the frequency of the beats (fb) is:

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with f1 the frequency of the first tuning fork and f2 the frequency of the second tuning fork, so we should solve

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4 0
3 years ago
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