Answer:
E1 = 10.15 * 10^4 N/C
E2 = 0
E3 = 10.15 *10^4 N/C
Explanation:
Given data:
Two 13 cm-long thin glass rods ( L ) = 0.13 m
charge (Q) = +11nC
distance between thin glass rods = 4 cm .
<u>Calculate the electric field strengths </u>
electric charge due to a single glass rod in the question ( E ) = 
equation 1 can be used to determine E1, E2 and E3 because the points lie within the two rods hence the net electric field produced will be equal to the difference in electric fields produced
applying equation 1 to determine E1
E1 = 
( distance from 1 rod is 0.01 m and from the other rod is 0.03 )
= 
= 10.15 * 10^4 N/C
applying equation 1 to determine E2
E2 = 
therefore E2 = 0
E1 = E3
hence E3 = 10.15*10^4 N/C
Explanation:
the other 40% is used to power the 60% making it only capable of 60% efficiency
Answer:
Explanation:
wave length of light λ = 623 x 10⁻⁹ m .
Distance of screen D = 76.5 x 10⁻² m
width of slit = d
Distance on the screen between the second order minimum and the central maximum = 2 λ D / d
1.11 x 10⁻² = (2 x 623 x 10⁻⁹ x 76.5 x 10⁻² )/ d
d = ( 2 x 623 x 10⁻⁹ x 76.5 x 10⁻²) / 1.11 x 10⁻²
= 85872.97 x 10⁻⁹
= 85.87297 x 10⁻⁶
= 85.87 μm
width a of the slit is = 85.87 μm
Answer:
The function has a maximum in 
The maximum is:
Explanation:
Find the first derivative of the function for the inflection point, then equal to zero and solve for x
Now find the second derivative of the function and evaluate at x = 3.
If 
the function has a maximum
If 
the function has a minimum
Note that:
the function has a maximum in
The maximum is:
Answer:
I believe <u>kinetic / potential</u>
Explanation:
