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bazaltina [42]
3 years ago
9

What aspect of bouncing balls relates to matter

Physics
1 answer:
Lynna [10]3 years ago
8 0

Answer: An aspect of the event of various types of balls bouncing off the same floor, being matter is that all the balls consist of matter. They all occupy space and have a form of energy when moved by a force, such as a person. And for energy, like I just said, when they bounce they create energy as they bounce up and down, so if the ball were to hit some other object, it would have an impact on the still object.

The combination of the material properties of a ball (surface textures, actual materials, amount of air, hardness/ softness, and so on) affects the height of its bounce.

Hope this helps.......... Stay safe and have a Merry Christmas!!!!!!!!!! :D

Explanation:

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What is the study of sound waves called?<br><br> short answer pls
sweet [91]

Answer:

Acoustics

Explanation: It’s the branch of physics that deals with the study of mechanical waves in gases, liquids, and solids including topics such as vibration, sound, ultrasound and infrasound.

7 0
3 years ago
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Which of the following is typically NOT a method scientist use to determine astronomic distances
tangare [24]
I think the answer is A
5 0
3 years ago
Two 75 W (120 V) lightbulbs are wired in series, then the combination is connected to a 120 V supply. Part A How much power is d
Elenna [48]

Answer:

<em>300 W</em>

<em></em>

Explanation:

power of each bulb P = 75 W

voltage in the circuit = 120 V

we know that electrical power P = IV    ....1

and V = IR

we can also say that I = V/R

substituting for I in  equation 1, we have

P = V^{2}/R    ....2

The total total power in the circuit = 75 x 2 = 150 W

from equation 2, we have

150 = 120^{2} /R

R = 120^{2}/150 = 96 Ω    this is the resistance of the whole circuit.

This resistance is due to the two light bulbs, for each light bulb since they are arranged in series

R = 96/2 = 48 Ω

From P =  V^{2}/R  

for each light bulb, power is

P = 120^{2} /48 = <em>300 W</em>

8 0
3 years ago
A 4.88 x 10-6 C charge moves 265 m/s
Alex73 [517]

Answer:

F=0N

Explanation:

From the question we are told that:

Charge Q=4.88 x 10-6 C

Velocity v= 265m/s

Angle \theta =0 \textdegree

Magnetic field B=0.0579T

Generally the equation for Force is mathematically given by

 F=Q(\=v*\=B)

 F=qvBsin\theta

Therefore

 F=qvBsin0 \textdegree

 F=0N

5 0
3 years ago
Read 2 more answers
Skater begins to spend with arms held out at shoulder height. The skater wants to match the speed of the spin to the beat of the
Aleksandr [31]

Answer:

the moment of inertia with the arms extended is Io and when the arms are lowered the moment

I₀/I > 1    ⇒   w > w₀

Explanation:

The angular momentum is conserved if the external torques in the system are zero, this is achieved because the friction with the ice is very small,

           L₀ = L_f

           I₀ w₀ = I w

          w =\frac{I_o}{I} w₀

where we see that the angular velocity changes according to the relation of the angular moments, if we approximate the body as a cylinder with two point charges, weight of the arms

          I₀ = I_cylinder + 2 m r²

where r is the distance from the center of mass of the arms to the axis of rotation, the moment of inertia of the cylinder does not change, therefore changing the distance of the arms changes the moment of inertia.

If we say that the moment of inertia with the arms extended is Io and when the arms are lowered the moment will be

        I <I₀

        I₀/I > 1    ⇒   w > w₀

therefore the angular velocity (rotations) must increase

in this way the skater can adjust his spin speed to the musician.

7 0
3 years ago
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