Answer:
a) 2nd case rate of rotation gives the greater speed for the ball
b) 1534.98 m/s^2
c) 1515.04 m/s^2
Explanation:
(a) v = ωR
when R = 0.60, ω = 8.05×2π
v = 0.60×8.05×2π = 30.34 m/s
Now in 2nd case
when R = 0.90, ω = 6.53×2π
v = 0.90×6.53×2π = 36.92 m/s
6.35 rev/s gives greater speed for the ball.
(b) a = ω^2 R = (8.05×2π)^2 )(0.60) = 1534.98 m/s^2
(c) a = ω^2 R = (6.53×2π)^2 )(0.90) = 1515.05 m/s^2
Answer:
a) d = 182.08 miles
b)
Explanation:
a) The distance can be found as follows:



b) The average speed can be calculated using the following equation:

Where "f" is for final and "i" for initial
I hope it helps you!
Answer:
The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

f= force
m=mass
a=acceleration
Explanation:
examples:
riding your bicycle
•your bicycle is the mass, your leg pushing in pedals of your bicycle is the force
pushing a box
•the box is the mass, you are pushing the box
setting a pencil down in a table
•the pencil is the mass, you are puting the pencil down
Answer:
45.44m/s
Explanation:
To solve this problem it is necessary to go back to the concepts related to the first law of thermodynamics,
in which it deepens on the conservation of the Energy.
The first law of Thermodynamics is given by the equation:

Where,
Heat transfer
Work
Flow mass
Velocity
Specific Enthalpy
Gravity
Height
From this equation we have that there is not Heat transfer, Work and changes in Height. Then,
Then our equation would be,

Solving for 

From the tables of ideal gas (air) at 216K we have,


From the tables at 250K, we have that

The velocity was previously given, then

Replacing in the equation:


Therefore the velocity of the air at the diffuser exit is 45.44m/s