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3 years ago

Why is this trendline wrong?

Mathematics

1 answer:

hichkok12 [17]3 years ago

8 0

Answer:

eff

Step-by-step explanation:

erv

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Complete the steps to simplify^5√4 x √2 . Rewrite using rational exponents.

ozzi

The answer is 2^(9/10). I did it assuming with the ^5 you mean the 5th root of 4

7 0

3 years ago

Read 2 more answers

Which of the following equations represent a proportional relationship

MAXImum [283]

A would be fine as your answer.

8 0

3 years ago

Consider these functions

Evgen [1.6K]

<h3>Answer: D) 31</h3>

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Explanation:

The expression g(f(2)) has f(2) as the inner function.

Let's compute f(2)

This means we plug x = 2 into the f(x) function

f(x) = 4x^3 - 10

f(x) = 4(x)^3 - 10

f(2) = 4(2)^3-10

f(2) = 4*8-10

f(2) = 32-10

f(2) = 22

Now we'll plug this into the g(x) function

This is because g(f(2)) = g(22). I've replaced f(2) with 22

So,

g(x) = (3x-4)/2

g(22) = (3*22-4)/2

g(22) = (66-4)/2

g(22) = 62/2

g(22) = 31

Therefore, g(f(2)) = 31

7 0

3 years ago

Help thankss <br>answer is <br><img src="https://tex.z-dn.net/?f=%20%28%20-%2014.0%29" id="TexFormula1" title=" ( - 14.0)" alt="

lyudmila [28]

We have point $P=(x_0,y_0)=(2,-4)$ , so first calculate $f'(x_0)$ . There will be:

$y=f(x)=2x^3-5x^2\\\\\\\\f'(x)=\big(2x^3-5x^2\big)'=\big(2x^3\big)'-\big(5x^2\big)'=2\big(x^3\big)'-5\big(x^2\big)'=\\\\=2\cdot3x^2-5\cdot2x=\boxed{6x^2-10x}\\\\\\\\f'(x_0)=f'(2)=6\cdot2^2-10\cdot2=6\cdot4-20=24-20=\boxed{4}$

Now, we can write the equation of the normal line as:

$y-y_0=-\dfrac{1}{f'(x_0)}(x-x_0)\\\\\\ y-(-4)=-\dfrac{1}{4}(x-2)\\\\\\y+4=-\dfrac{1}{4}x+\dfrac{1}{2}\\\\\\y=-\dfrac{1}{4}x+\dfrac{1}{2}-4\\\\\\\boxed{y=-\dfrac{1}{4}x-\dfrac{7}{2}}$

Normal line (and every line) crosses x-axis when y = 0, so coordinates of A:

$\boxed{y=0}\qquad\qquad\text{and}\\\\\\y=-\dfrac{1}{4}x-\dfrac{7}{2}\\\\\\
0=-\dfrac{1}{4}x-\dfrac{7}{2}\\\\\\\dfrac{1}{4}x=-\dfrac{7}{2}\quad|\cdot4\\\\\\x=-\dfrac{7\cdot4}{2}\\\\\\x=-7\cdot2\\\\\\\boxed{x=-14}\\\\\\\boxed{A=(-14,0)}$

8 0

3 years ago

Two airplanes leave an airport at the same time and travel in opposite directions. One plane travels 60km\h slower than the othe

DanielleElmas [232]

Answer:

4 V + 4 (V - 60) = D where D is distance apart after 4 hrs

8 V - 240 = 7304

V = 943 km/hr

and V2 = 943 - 60 = 883 km/hr where second plane is 60 km/hr slower

6 0

2 years ago

Why is this trendline wrong?​

Why is this trendline wrong?